APSC 171

Queen's

Course Overview
Grade Boosters

Lessons & Practice

I. Welcome

1. Derivatives
3hr
2. Vector-Valued Functions
2.9hr
3. Derivatives of Vector Valued Functions
2hr

I Welcome

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Mock Exam Walkthrough
Test 1 Mock
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Releases: May 25, 12:09am

Welcome to Integral Calculus!

My name is Corey and I'm the instructor for this course. Feel free to go through this course at your own pace.
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Answered
L
Layan E
Use the Intermediate Value Theorem to show that thereis a root of the given equation in the specified interval.Use the Intermediate Value Theorem to show that thereis a root of the given equation in the specified interval.
sin(x)=x2−x, x∈(1,2)
C
Corey M
Instructor
While this isn't quite the place for this question (please refer to the IVT section in the course), and we can't really just solve random problems for you, I can give you a bit of a hint: You could try moving everything to one side of the equation and treating it like a function, and then see if you can't find function values within your specified range that return a positive value and a negative value (another hint: try the endpoints of your interval first). If you're able to do that, then the IVT tells us that there should exist a function input between those two points that returns 0 or, in other words, that is a root.