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Practice: Separable DE
Related Topics
Wize University Calculus 2 Textbook > Differential Equations
Separable Differential Equations
6 Activities
Solve
d
y
d
x
=
4
e
5
x
y
\displaystyle \frac{dy}{dx}=\frac{4e^{5x}}{y}
d
x
d
y
=
y
4
e
5
x
y
=
±
4
5
e
5
x
+
C
y=\pm\sqrt{\frac{4}{5}e^{5x}+C}
y
=
±
5
4
e
5
x
+
C
y
=
8
5
e
5
x
+
C
y=\frac{8}{5}e^{5x}+C
y
=
5
8
e
5
x
+
C
y
=
±
8
5
e
5
x
+
C
y=\pm\sqrt{\frac{8}{5}e^{5x}+C}
y
=
±
5
8
e
5
x
+
C
y
=
20
e
5
x
+
C
y=20e^{5x}+C
y
=
20
e
5
x
+
C
y
=
±
20
e
5
x
+
C
y=\pm\sqrt{20e^{5x}+C}
y
=
±
20
e
5
x
+
C
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Check Submission
More Separable Differential Equations Questions:
Practice: Separable DE
Practice Question
Solve
d
y
d
x
=
4
e
5
x
y
\displaystyle \frac{dy}{dx}=\frac{4e^{5x}}{y}
d
x
d
y
=
y
4
e
5
x
Practice: Separable with Initial Condition
Solve the differential equation
d
y
d
x
=
2
x
+
1
y
3
\dfrac{dy}{dx}=\dfrac{2x+1}{y^3}
d
x
d
y
=
y
3
2
x
+
1
given that
y
(
0
)
=
2
y\left(0\right)=2
y
(
0
)
=
2
Practice: Separable with Initial Condition
Q:
\textbf{Q:}
Q:
Solve the differential equation
d
y
d
x
=
2
x
+
1
y
3
\dfrac{dy}{dx}=\dfrac{2x+1}{y^3}
d
x
d
y
=
y
3
2
x
+
1
given that
y
(
0
)
=
2
y\left(0\right)=2
y
(
0
)
=
2
Practice: Separable DE
Practice Question
Solve
d
y
d
x
=
4
e
5
x
y
\displaystyle \frac{dy}{dx}=\frac{4e^{5x}}{y}
d
x
d
y
=
y
4
e
5
x