Randomness and probability
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You are one of three players remaining in a poker tournament. The total prize is $1,000 where the winner gets $750 and the player who gets second place wins $250. The third-place finisher wins nothing.
Currently, you have the most chips ($$$). Player A has the least amount of chips ($). You are dealt with ace-queen suited. The other two players went all-in with pairs! It is your turn.
If you go on all-in, the pot will be so massive that whoever wins this crucial round will win the tournament. The photo shows that, if you go all-in (or simply call), you have a 27.91% chance of winning this round and knocking both players out - thus winning the tournament! But if you go all-in and lose this round, you will lose a lot of chips and will have no chance in winning the tournament. Instead, you will settle for second or third place, depending if another player gets knocked out or not after this round. If Player A wins this round, all three players remain but Player A will be guaranteed to win the tournament, forcing you and Player B to fight for second place. If Player B wins this round, Player A will be knocked out and you will settle for second place.
If you fold, you will have enough chips to play another round but the chance of you winning the tournament drops to 15%. What should you do in this round?
