19.4F_133_8.2_Mock_F1_$\tkco{eg2}$_$\key{Final}$_Builder_$\tkcth{8.2.}\tkcf{2}$_

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Show that, in the case that the matrix A\A is invertible, the least squares solution corresponding to the system:
Ax  =  b, \A \, \vx \; = \; \vb,
is the same as the solution to the system itself.

In other words, show that the solution to the system:
 ⁣M ⁣  T ⁣M ⁣  x  =   ⁣M ⁣  Tb \M^T\M \, \vx^{\,*} \; = \; \M^T \vb
and the solution to the system:
 ⁣M ⁣  x  =  b \M \vx \; = \; \vb
are the same.

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