Create a free account to get started

Unlock full course notes by signing up

  • Video lessons taught by top educators
  • Practice questions with guided solutions
  • Written review notes for reference
  • Expert answers anytime from course tutors

Vectors and Their Components


  • A Vector is a quantity that has both magnitude and direction such as velocity.
  • A Scalar has magnitude but no direction such as speed.
  • Two vectors are equal to each other as long as they have the same size and direction
  • Vectors can be written in terms of their components based on different coordinate systems
  • The most common coordinate system is XYZ -coordinate system which is also known as Cartesian coordinate system.
  • Theses components are the shadow of the vector on different axis of the coordinate system
  • A given vector a⃗\vec{a} in 2D space is shown as:
a⃗=(ax,ay)=axi^+ayj^\boxed{\vec{a}=\left( a_x,a_y\right )=a_x\hat{i}+a_y\hat{j} }


- where vectors , i^\hat{i} and j^\hat{j} are basic unit vectors in xx and yy directions, respectively. These unit vectors are:

i^=(1,0) j^=(0,1)\begin{array}{l}\hat{i}=(1,0)\\\ \hat{j}=(0,1)\end{array}
  • Unit vectors are vectors with length equal to 1 which are used to show directions.
  • axa_xand aya_yare called components of vector a⃗\vec{a}





Create a free account to get started

Unlock full course notes by signing up

  • Video lessons taught by top educators
  • Practice questions with guided solutions
  • Written review notes for reference
  • Expert answers anytime from course tutors

ٰVector's Magnitude

Magnitude of a 2D Vector

We can calculate the magnitude (a.k.a. length or size) of a vector in 2D using Pythagorean's Theorem:

Image illustrating Vector's Magnitude (2D & 3D)



Magnitude of a 3D Vector

Similarly, We can calculate the magnitude of a vector in 3D using an extension of this formula.






Create a free account to get started

Unlock full course notes by signing up

  • Video lessons taught by top educators
  • Practice questions with guided solutions
  • Written review notes for reference
  • Expert answers anytime from course tutors

Components of a Vector Using the Angle It Makes Respect to x or y Axis


In many problems we need to find the components of a vector along different directions. For these problems we use trigonometric relationship using right triangle formed by the vector as the hypotenuse and components as the two other sides of the triangle.




Example:

Consider the following vector which makes an angle of θ\thetarespect to the x-axis (horizontal direction)


Image illustrating Components of a Vector Using the Angle It Makes Respect to x or y Axis


Components of this vector along x and y directions could be found as:

vx=∣v⃗∣cos⁡θvy=∣v⃗∣sin⁡θ\begin{array}{l}v_x=|\vec{v}|\cos\theta\\v_y=|\vec{v}|\sin\theta\end{array}





We can find the length of this vector and the angle it makes respect to horizontal x-axis using the following equation:

  • Length of a vector in 2-D space is equal to:
∣v⃗∣=vx2+vy2\boxed{|\vec{v}|=\sqrt{v_x^2+v_y^2}}
  • The direction of a vector usually is reported by the angle it makes with positive xx-axis (Counter-clockwise) using following formula:
θ=tan⁡−1(vyvx)\boxed{\theta=\tan^{-1}\left(\frac{v_y}{v_x}\right)}




Create a free account to get started

Unlock full course notes by signing up

  • Video lessons taught by top educators
  • Practice questions with guided solutions
  • Written review notes for reference
  • Expert answers anytime from course tutors

Example: Vector Connecting Two Points


If A(1,2)A\left(1,2\right) and B(−1,3)B\left(-1,3\right), calculate AB→\overrightarrow{AB}, length of AB→\overrightarrow{AB} and the angle it makes with positive xx-axis.


Solution:


AB→=B→−A→ =(−1,3)−(1,2)=(−1−1,3−2)=(−2,1)\begin{array}{rl}\overrightarrow{AB}=\overrightarrow{B}-\overrightarrow{A}\ = &\left(-1,3\right)-\left(1,2\right)\\=&(-1-1,3-2)=(-2,1)\end{array}



Image illustrating Example: Vector Between Two Points



∣AB→∣=(−2)2+12=5\left|\overrightarrow{AB}\right|=\sqrt{\left(-2\right)^2+1^2}=\sqrt{5}


 θ=180−tan⁡−1∣AByABx∣=180−tan⁡−1∣1−2∣=153.43°\ \theta=180-\tan^{-1}\left|\frac{AB_y}{AB_x}\right|=180-\tan^{-1}\left|\frac{1}{-2}\right|=153.43\degree




A football is thrown with a horizontal velocity of 10m/s and a vertical velocity of 4.25 m/s. What is football's velocity?



Choose an answer

Create a free account to get started

Unlock full course notes by signing up

  • Video lessons taught by top educators
  • Practice questions with guided solutions
  • Written review notes for reference
  • Expert answers anytime from course tutors