Given the function f(x)=(g(x))/(h(x))-e^xcos x, g((π)/2)=2, g'((π)/2)=3, h((π)/…

Given the function f(x)=g(x)h(x)excosxf\left(x\right)=\frac{g\left(x\right)}{h\left(x\right)}-e^x\cos x, g(π2)=2g\left(\frac{\pi}{2}\right)=2, g(π2)=3g'\left(\frac{\pi}{2}\right)=3, h(π2)=1h\left(\frac{\pi}{2}\right)=1, and h(π2)=2h'\left(\frac{\pi}{2}\right)=2, find f(π2)f'\left(\frac{\pi}{2}\right).


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