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The Chain Rule" Derivatives of Trigonometric Functions
Related Topics
Wize University Calculus 1 Textbook > Derivatives
The Chain Rule
3 Activities
Wize University Calculus 1 Textbook > Derivatives
Derivatives of Trig Functions
6 Activities
Calculate the derivative of the function
f
(
x
)
=
tan
(
x
3
)
f\left(x\right)=\sqrt{\tan\left(x^3\right)}
f
(
x
)
=
tan
(
x
3
)
f
′
(
x
)
=
3
sec
2
(
x
3
)
2
tan
(
x
3
)
f'\left(x\right)=\frac{3\sec^2\left(x^3\right)}{2\sqrt{\tan\left(x^3\right)}}
f
′
(
x
)
=
2
t
a
n
(
x
3
)
3
s
e
c
2
(
x
3
)
f
′
(
x
)
=
sec
2
(
x
3
)
tan
(
x
3
)
f'\left(x\right)=\frac{\sec^2\left(x^3\right)}{\sqrt{\tan\left(x^3\right)}}
f
′
(
x
)
=
t
a
n
(
x
3
)
s
e
c
2
(
x
3
)
f
′
(
x
)
=
3
x
2
sec
2
(
x
3
)
2
tan
(
x
3
)
f'\left(x\right)=\frac{3x^2\sec^2\left(x^3\right)}{2\sqrt{\tan\left(x^3\right)}}
f
′
(
x
)
=
2
t
a
n
(
x
3
)
3
x
2
s
e
c
2
(
x
3
)
f
′
(
x
)
=
3
sec
2
(
x
3
)
tan
(
x
3
)
f'\left(x\right)=\frac{3\sec^2\left(x^3\right)}{\sqrt{\tan\left(x^3\right)}}
f
′
(
x
)
=
t
a
n
(
x
3
)
3
s
e
c
2
(
x
3
)
I don't know
Check Submission
More The Chain Rule Questions:
The Chain Rule
Q
:
\bf{Q:}
Q
:
Find
(
3
3
x
−
x
4
+
2
cos
−
1
(
x
)
−
2025
)
′
(3^{3x-x^{4}}+2^{\cos^{-1}(x)}-2025)'
(
3
3
x
−
x
4
+
2
c
o
s
−
1
(
x
)
−
2025
)
′
Derivatives
Find the derivative of the following functions at the given values
a)
f
(
x
)
=
arcsin
(
x
2
)
x
3
−
1
f\left(x\right)=\frac{\arcsin\left(x^2\right)}{x^3-1}
f
(
x
)
=
x
3
−
1
a
r
c
s
i
n
(
x
2
)
at
x
=
0
x=0
x
=
0
b)
g
(
x
)
=
(
cos
x
)
e
x
g\left(x\right)=\left(\cos x\right)^{e^x}
g
(
x
)
=
(
cos
x
)
e
x
at
x
=
0
x=0
x
=
0
Finding a Derivative
If
f
(
x
)
=
tan
−
1
(
3
sin
x
)
f(x)=\tan^{-1}\left(3^{\sin x}\right)
f
(
x
)
=
tan
−
1
(
3
s
i
n
x
)
, find
f
′
(
π
)
f'(\pi)
f
′
(
π
)
.
The Chain Rule
Q
:
\bf{Q:}
Q
:
Find
(
3
3
x
−
x
4
+
2
c
o
s
−
1
(
x
)
−
2019
)
′
(3^{3x-x^4}+2^{cos^{-1}(x)}-2019)'
(
3
3
x
−
x
4
+
2
co
s
−
1
(
x
)
−
2019
)
′
The Chain Rule
Find the derivative of
h
(
x
)
=
f
(
g
(
x
)
)
h(x)=f(g(x))
h
(
x
)
=
f
(
g
(
x
))
if
f
(
x
)
=
x
2
+
1
f(x)=x^2+1
f
(
x
)
=
x
2
+
1
and
g
(
x
)
=
3
x
g(x)=3\sqrt{x}
g
(
x
)
=
3
x
.
The Chain Rule
Find the derivative of
h
(
x
)
=
f
(
g
(
x
)
)
h(x)=f(g(x))
h
(
x
)
=
f
(
g
(
x
))
if
f
(
x
)
=
x
2
+
1
f(x)=x^2+1
f
(
x
)
=
x
2
+
1
and
g
(
x
)
=
3
x
g(x)=3\sqrt{x}
g
(
x
)
=
3
x
.
The Chain Rule
Find
g
′
(
0
)
g'(0)
g
′
(
0
)
for
g
(
x
)
=
f
(
x
2
)
+
f
(
x
)
,
g(x)=\sqrt{f(x^2)} + f(x),
g
(
x
)
=
f
(
x
2
)
+
f
(
x
)
,
given
f
(
0
)
=
2
and
f
′
(
0
)
=
1.
f(0)=2 \text{ and }f'(0)=1.
f
(
0
)
=
2
and
f
′
(
0
)
=
1.
The Chain Rule
If
2
−
g
(
x
)
=
x
2
+
2
[
f
(
x
)
]
2
−
x
3
g
(
x
)
2-g\left(x\right)=x^2+2\left[f\left(x\right)\right]^2-x^3g\left(x\right)
2
−
g
(
x
)
=
x
2
+
2
[
f
(
x
)
]
2
−
x
3
g
(
x
)
,
f
(
0
)
=
1
,
f
′
(
0
)
=
−
2
,
g
(
0
)
=
−
1
and
g
′
′
(
0
)
=
3
f\left(0\right)=1\ ,\ f'\left(0\right)=-2,\ g\left(0\right)=-1\ \text{and}\ \ g''\left(0\right)=3
f
(
0
)
=
1
,
f
′
(
0
)
=
−
2
,
g
(
0
)
=
−
1
and
g
′′
(
0
)
=
3
, then the value of
f
′
′
(
0
)
f''\left(0\right)
f
′′
(
0
)
is equal to
Find
g
′
(
0
)
g^{\prime}(0)
g
′
(
0
)
for
g
(
x
)
=
f
(
x
2
)
+
f
(
x
)
g(x)=\sqrt{f(x^2)}+f(x)
g
(
x
)
=
f
(
x
2
)
+
f
(
x
)
, given
f
(
0
)
=
2
f(0)=2
f
(
0
)
=
2
and
f
′
(
0
)
=
1
f^{\prime}(0)=1
f
′
(
0
)
=
1
.
The Chain Rule
Find the derivative of the following function.
f
(
x
)
=
(
2
x
+
1
x
2
+
1
)
3
\displaystyle f(x)=\left(\frac{2x+1}{x^2+1}\right)^3
f
(
x
)
=
(
x
2
+
1
2
x
+
1
)
3
Find
d
d
x
(
arctan
(
e
tan
x
)
)
\frac{d}{dx}\left(\arctan\left(e^{\tan x}\right)\right)
d
x
d
(
arctan
(
e
t
a
n
x
)
)
.
The Chain Rule
The derivative of
y
=
3
e
x
y=3^{e^x}
y
=
3
e
x
is
The Chain Rule
The derivative of
y
=
3
e
x
y=3^{e^x}
y
=
3
e
x
is
The Chain Rule
The derivative of
y
=
3
e
x
y=3^{e^x}
y
=
3
e
x
is
The Chain Rule
The derivative of
y
=
3
e
x
y=3^{e^x}
y
=
3
e
x
is
Practice: Chain Rule
Find the derivative of
y
=
ln
(
arctan
x
)
y=\ln(\arctan x)
y
=
ln
(
arctan
x
)
Find
d
d
x
(
arctan
(
e
tan
x
)
)
\frac{d}{dx}\left(\arctan\left(e^{\tan x}\right)\right)
d
x
d
(
arctan
(
e
t
a
n
x
)
)
.
The Chain Rule: Finding a derivative
Find the derivative of
f
(
x
)
=
cos
(
e
2
x
)
f\left(x\right)=\sqrt{\cos\left(e^{2x}\right)}
f
(
x
)
=
cos
(
e
2
x
)
Practice: trig and inverse trig derivatives
Practice: trig and inverse trig derivatives
Find the derivative of the following trigonometric and inverse trigonometric functions:
a)
f
(
x
)
=
arcsin
(
3
x
2
)
f(x)=\arcsin(3x^2)
f
(
x
)
=
arcsin
(
3
x
2
)
The Chain Rule
Given this table of values for
f
,
g
,
f
′
,
and
g
′
f,\ g,\ f',\ \text{and}\ g'
f
,
g
,
f
′
,
and
g
′
below, answer the following questions.
x
f
(
x
)
f
′
(
x
)
f
′
′
(
x
)
g
(
x
)
g
′
(
x
)
0
0
−
1
−
5
2
3
π
2
π
1
0
4
5
2
−
2
−
4
10
π
2
−
3
\begin{array}{|c|c|c|c|c|c|} \hline x&f(x)&f'(x)&f''(x)&g(x)&g'(x)\\ \hline 0&0&-1&-5&2&3\\ \hline \frac{\pi}{2}&\pi&1&0&4&5\\ \hline 2&-2&-4&10&\frac{\pi}{2}&-3\\ \hline \end{array}
x
0
2
π
2
f
(
x
)
0
π
−
2
f
′
(
x
)
−
1
1
−
4
f
′′
(
x
)
−
5
0
10
g
(
x
)
2
4
2
π
g
′
(
x
)
3
5
−
3
The Chain Rule
Q
:
\bf{Q:}
Q
:
Find
(
3
3
x
−
x
4
+
2
c
o
s
−
1
(
x
)
−
2019
)
′
(3^{3x-x^4}+2^{cos^{-1}(x)}-2019)'
(
3
3
x
−
x
4
+
2
co
s
−
1
(
x
)
−
2019
)
′
The Chain Rule
Find the derivative of
h
(
x
)
=
f
(
g
(
x
)
)
h(x)=f(g(x))
h
(
x
)
=
f
(
g
(
x
))
if
f
(
x
)
=
x
2
+
1
f(x)=x^2+1
f
(
x
)
=
x
2
+
1
and
g
(
x
)
=
3
x
g(x)=3\sqrt{x}
g
(
x
)
=
3
x
.
Practice: Chain Rule with Given Values
Q.
\textbf{Q.}
Q.
Given that
g
(
1
)
=
g
′
(
1
)
=
1
g(1)=g^{\prime}(1)=1
g
(
1
)
=
g
′
(
1
)
=
1
, find
f
′
(
π
/
2
)
f^{\prime}(\pi/2)
f
′
(
π
/2
)
if
f
(
x
)
=
g
(
sin
x
)
x
+
1
\displaystyle f(x)=\frac{\sqrt{g(\sin{x})}}{x+1}
f
(
x
)
=
x
+
1
g
(
sin
x
)
.
Practice: Chain Rule with Given Values
Q:
\textbf{Q:}
Q:
Given that
f
(
1
)
=
5
,
g
(
1
)
=
−
2
,
f
′
(
1
)
=
2
f(1)=5,\ g(1)=-2,\ f'(1)=2
f
(
1
)
=
5
,
g
(
1
)
=
−
2
,
f
′
(
1
)
=
2
and
g
′
(
1
)
=
−
1
/
2
g'(1)=-1/2
g
′
(
1
)
=
−
1/2
, find the derivative of
f
(
x
)
−
g
2
(
x
)
\sqrt{f(x)-g^2(x)}
f
(
x
)
−
g
2
(
x
)
at
x
=
1
x=1
x
=
1
.
The Quotient and Chain Rules
Let
f
(
x
)
=
x
2
−
6
x
−
3
\displaystyle f(x) = \frac{\sqrt{x^2 - 6}}{x - 3}
f
(
x
)
=
x
−
3
x
2
−
6
.
The chain rule
Find the derivative of
h
(
x
)
=
log
(
cos
(
x
)
)
h(x) = \log(\cos(x))
h
(
x
)
=
lo
g
(
cos
(
x
))
. Remember that
log
x
=
log
e
x
=
ln
x
\log x = \log_e x = \ln x
lo
g
x
=
lo
g
e
x
=
ln
x
.
Derivatives
Find the derivative of the following functions at the given values
a)
f
(
x
)
=
arcsin
(
x
2
)
x
3
−
1
f\left(x\right)=\frac{\arcsin\left(x^2\right)}{x^3-1}
f
(
x
)
=
x
3
−
1
a
r
c
s
i
n
(
x
2
)
at
x
=
0
x=0
x
=
0
b)
g
(
x
)
=
(
cos
x
)
e
x
g\left(x\right)=\left(\cos x\right)^{e^x}
g
(
x
)
=
(
cos
x
)
e
x
at
x
=
0
x=0
x
=
0
The chain rule: Logarithmic Derivatives
The derivative of
log
3
(
e
3
x
)
\log_3\left(e^{3x}\right)
lo
g
3
(
e
3
x
)
is
The chain rule
The derivative of
y
=
(
2
−
x
7
)
500
y=\left(2-x^7\right)^{500}
y
=
(
2
−
x
7
)
500
is
The Chain Rule
If
2
−
g
(
x
)
=
x
2
+
2
[
f
(
x
)
]
2
−
x
3
g
(
x
)
2-g\left(x\right)=x^2+2\left[f\left(x\right)\right]^2-x^3g\left(x\right)
2
−
g
(
x
)
=
x
2
+
2
[
f
(
x
)
]
2
−
x
3
g
(
x
)
,
f
(
0
)
=
1
,
f
′
(
0
)
=
−
2
,
g
(
0
)
=
−
1
and
g
′
′
(
0
)
=
3
f\left(0\right)=1\ ,\ f'\left(0\right)=-2,\ g\left(0\right)=-1\ \text{and}\ \ g''\left(0\right)=3
f
(
0
)
=
1
,
f
′
(
0
)
=
−
2
,
g
(
0
)
=
−
1
and
g
′′
(
0
)
=
3
, then the value of
f
′
′
(
0
)
f''\left(0\right)
f
′′
(
0
)
is equal to
Find the derivative of
h
(
x
)
=
f
(
g
(
x
)
)
if
f
(
x
)
=
x
2
+
1
h(x)=f(g(x))\,\, \text{ if }\, f(x)=x^2+1
h
(
x
)
=
f
(
g
(
x
))
if
f
(
x
)
=
x
2
+
1
and
g
(
x
)
=
3
x
g(x)=3\sqrt{x}
g
(
x
)
=
3
x
.
Find
g
′
(
0
)
g^{\prime}(0)
g
′
(
0
)
for
g
(
x
)
=
f
(
x
2
)
+
f
(
x
)
g(x)=\sqrt{f(x^2)}+f(x)
g
(
x
)
=
f
(
x
2
)
+
f
(
x
)
, given
f
(
0
)
=
2
f(0)=2
f
(
0
)
=
2
and
f
′
(
0
)
=
1
f^{\prime}(0)=1
f
′
(
0
)
=
1
.
Find the derivative of
h
(
x
)
=
f
(
g
(
x
)
)
if
f
(
x
)
=
x
2
+
1
h(x)=f(g(x))\,\, \text{ if }\, f(x)=x^2+1
h
(
x
)
=
f
(
g
(
x
))
if
f
(
x
)
=
x
2
+
1
and
g
(
x
)
=
3
x
g(x)=3\sqrt{x}
g
(
x
)
=
3
x
.
Find the derivative of the following function.
f
(
x
)
=
(
2
x
+
1
x
2
+
1
)
3
\displaystyle f(x)=\left(\frac{2x+1}{x^2+1}\right)^3
f
(
x
)
=
(
x
2
+
1
2
x
+
1
)
3
The Chain Rule
Find
g
′
(
0
)
g'(0)
g
′
(
0
)
for
g
(
x
)
=
f
(
x
2
)
+
f
(
x
)
,
g(x)=\sqrt{f(x^2)} + f(x),
g
(
x
)
=
f
(
x
2
)
+
f
(
x
)
,
given
f
(
0
)
=
2
and
f
′
(
0
)
=
1.
f(0)=2 \text{ and }f'(0)=1.
f
(
0
)
=
2
and
f
′
(
0
)
=
1.
The Chain Rule
Compute the derivative of
f
(
x
)
=
x
4
+
4
x
4
+
4
f(x) = \sqrt{x^4 + \frac{4}{x^4}+4}
f
(
x
)
=
x
4
+
x
4
4
+
4
Practice: Chain Rule
Find the derivative of the following function:
y
=
sin
(
x
)
y=\sin(\sqrt{x})
y
=
sin
(
x
)
Practice: Complicated Chain-Rule
Find an expression for the derivative of the following function:
f
(
x
)
=
cos
(
e
2
x
)
f\left(x\right)=\sqrt{\cos \left(e^{2x}\right)}
f
(
x
)
=
cos
(
e
2
x
)
Practice: Chain Rule
Find the derivative of the following function:
y
=
e
sin
(
x
)
y=e^{\sin(\sqrt{x})}
y
=
e
s
i
n
(
x
)
Find the derivative of the following function.
f
(
x
)
=
arcsinx
\displaystyle f(x)=\sqrt{\text{arcsin{x}}}
f
(
x
)
=
arcsin
x
The Chain Rule
Q
:
\bf{Q:}
Q
:
Find
(
3
3
x
−
x
4
+
2
c
o
s
−
1
(
x
)
−
2019
)
′
(3^{3x-x^4}+2^{cos^{-1}(x)}-2019)'
(
3
3
x
−
x
4
+
2
co
s
−
1
(
x
)
−
2019
)
′
The Chain Rule
Find the derivative of
h
(
x
)
=
f
(
g
(
x
)
)
h(x)=f(g(x))
h
(
x
)
=
f
(
g
(
x
))
if
f
(
x
)
=
x
2
+
1
f(x)=x^2+1
f
(
x
)
=
x
2
+
1
and
g
(
x
)
=
3
x
g(x)=3\sqrt{x}
g
(
x
)
=
3
x
.
Practice: Chain Rule with Given Values
Q.
\textbf{Q.}
Q.
Given that
g
(
1
)
=
g
′
(
1
)
=
1
g(1)=g^{\prime}(1)=1
g
(
1
)
=
g
′
(
1
)
=
1
, find
f
′
(
π
/
2
)
f^{\prime}(\pi/2)
f
′
(
π
/2
)
if
f
(
x
)
=
g
(
sin
x
)
x
+
1
\displaystyle f(x)=\frac{\sqrt{g(\sin{x})}}{x+1}
f
(
x
)
=
x
+
1
g
(
sin
x
)
.
Practice: Chain Rule with Given Values
Q:
\textbf{Q:}
Q:
Given that
f
(
1
)
=
5
,
g
(
1
)
=
−
2
,
f
′
(
1
)
=
2
f(1)=5,\ g(1)=-2,\ f'(1)=2
f
(
1
)
=
5
,
g
(
1
)
=
−
2
,
f
′
(
1
)
=
2
and
g
′
(
1
)
=
−
1
/
2
g'(1)=-1/2
g
′
(
1
)
=
−
1/2
, find the derivative of
f
(
x
)
−
g
2
(
x
)
\sqrt{f(x)-g^2(x)}
f
(
x
)
−
g
2
(
x
)
at
x
=
1
x=1
x
=
1
.
Given the information
g
(
x
)
=
1
+
[
f
(
x
)
]
2
such that
f
(
1
)
=
2
,
f
′
(
1
)
=
−
3
g(x)=\sqrt{1+[f(x)]^2} \ \text{ such that } f(1)=2,f'(1)=-3
g
(
x
)
=
1
+
[
f
(
x
)
]
2
such that
f
(
1
)
=
2
,
f
′
(
1
)
=
−
3
. Find
g
′
(
1
)
.
g'(1).
g
′
(
1
)
.
Express your answer as a fraction in lowest terms. If the answer is negative, put the negative sign in front of the entire fraction.
The Chain Rule
If
g
(
t
)
=
9
+
f
(
t
)
3
g\left(t\right)=\sqrt[3]{9+f(t)}
g
(
t
)
=
3
9
+
f
(
t
)
, write an expression for the derivative
g
′
(
t
)
g'\left(t\right)
g
′
(
t
)
The Chain Rule
Find the derivative of the following function.
f
(
x
)
=
(
2
x
+
1
x
2
+
1
)
3
\displaystyle f(x)=\left(\frac{2x+1}{x^2+1}\right)^3
f
(
x
)
=
(
x
2
+
1
2
x
+
1
)
3
Practice: Chain Rule
Find the derivative of
y
=
ln
(
arctan
x
)
y=\ln(\arctan x)
y
=
ln
(
arctan
x
)
Find
d
d
x
(
arctan
(
e
tan
x
)
)
\frac{d}{dx}\left(\arctan\left(e^{\tan x}\right)\right)
d
x
d
(
arctan
(
e
t
a
n
x
)
)
.
Practice: trig and inverse trig derivatives
Practice: trig and inverse trig derivatives
Find the derivative of the following trigonometric and inverse trigonometric functions:
a)
f
(
x
)
=
arcsin
(
3
x
2
)
f(x)=\arcsin(3x^2)
f
(
x
)
=
arcsin
(
3
x
2
)
The Chain Rule: Finding a derivative
Find the derivative of
f
(
x
)
=
cos
(
e
2
x
)
f\left(x\right)=\sqrt{\cos\left(e^{2x}\right)}
f
(
x
)
=
cos
(
e
2
x
)
(Duplicated)
Find
f
′
(
1
)
f'\left(1\right)
f
′
(
1
)
if
f
(
x
)
=
x
2
g
(
x
)
f\left(x\right)=\sqrt{x^2\ g\left(x\right)}
f
(
x
)
=
x
2
g
(
x
)
,
g
(
1
)
=
1
g\left(1\right)=1
g
(
1
)
=
1
and
g
′
(
1
)
=
2
g'\left(1\right)=2
g
′
(
1
)
=
2
.
(Duplicated)
If
f
(
x
)
=
(
g
(
x
)
−
h
(
x
)
)
5
f\left(x\right)=\left(g\left(x\right)-h\left(x\right)\right)^5
f
(
x
)
=
(
g
(
x
)
−
h
(
x
)
)
5
,
g
(
0
)
=
2
,
h
(
0
)
=
0
,
g
′
(
0
)
=
6
g\left(0\right)=2,\ h\left(0\right)=0,\ g'\left(0\right)=6
g
(
0
)
=
2
,
h
(
0
)
=
0
,
g
′
(
0
)
=
6
, and
h
′
(
0
)
=
−
4
h'\left(0\right)=-4
h
′
(
0
)
=
−
4
, find
f
′
(
0
)
f'\left(0\right)
f
′
(
0
)
.
The Chain Rule
The derivative of
y
=
3
e
x
y=3^{e^x}
y
=
3
e
x
is
The Chain Rule
Given this table of values for
f
,
g
,
f
′
,
and
g
′
f,\ g,\ f',\ \text{and}\ g'
f
,
g
,
f
′
,
and
g
′
below, answer the following questions.
x
f
(
x
)
f
′
(
x
)
f
′
′
(
x
)
g
(
x
)
g
′
(
x
)
0
0
−
1
−
5
2
3
π
2
π
1
0
4
5
2
−
2
−
4
10
π
2
−
3
\begin{array}{|c|c|c|c|c|c|} \hline x&f(x)&f'(x)&f''(x)&g(x)&g'(x)\\ \hline 0&0&-1&-5&2&3\\ \hline \frac{\pi}{2}&\pi&1&0&4&5\\ \hline 2&-2&-4&10&\frac{\pi}{2}&-3\\ \hline \end{array}
x
0
2
π
2
f
(
x
)
0
π
−
2
f
′
(
x
)
−
1
1
−
4
f
′′
(
x
)
−
5
0
10
g
(
x
)
2
4
2
π
g
′
(
x
)
3
5
−
3
Finding a Derivative
Practice: Finding a Derivative
(
tan
−
1
(
3
sin
x
)
)
′
∣
x
=
π
=
\left(\tan^{-1}\left(3^{\sin x}\right)\right)'|_{x=\pi}=
(
tan
−
1
(
3
s
i
n
x
)
)
′
∣
x
=
π
=
Practice: The Chain Rule
Find the derivative of the following function
y
=
e
sin
x
y=e^{\sin\sqrt{x}}
y
=
e
s
i
n
x
Derivatives: Trigonometric and Exponential Functions
Calculate the derivative of the following functions.
f
(
x
)
=
tan
(
arccos
(
e
4
x
)
)
\displaystyle f(x)=\tan(\text{arccos}(e^{4x}))
f
(
x
)
=
tan
(
arccos
(
e
4
x
))
More Derivatives of Trig Functions Questions:
Quotient with Trig
Find the derivative of
h
(
t
)
=
cos
t
sin
t
(
1
+
cos
t
)
\displaystyle h(t)=\frac{\cos t}{\sin t(1+\cos t)}
h
(
t
)
=
sin
t
(
1
+
cos
t
)
cos
t
Practice: Equation of Tangent Line
Find the equation of the tangent line to the graph
y
=
sin
x
+
3
x
2
cos
x
y=\sin x+3x^2\cos x
y
=
sin
x
+
3
x
2
cos
x
at the point where
x
=
π
2
x=\frac{\pi}{2}
x
=
2
π
.
Practice: Equation of Tangent Line
Practice: Equation of Tangent Line
Find the equation of the tangent line to the graph
y
=
sin
x
+
3
x
2
cos
x
y=\sin x+3x^2\cos x
y
=
sin
x
+
3
x
2
cos
x
at the point where
x
=
π
2
x=\frac{\pi}{2}
x
=
2
π
.
Find the derivative of 𝑓(𝑥) = 𝑒
𝑥
tan 𝑥 + 3.
Differentiation Rules
Find
d
d
x
(
sin
2
x
+
π
+
cos
2
x
+
5
7
)
\frac{d}{dx}(\sin^2{x}+\sqrt\pi+\cos^2{x}+5^7)
d
x
d
(
sin
2
x
+
π
+
cos
2
x
+
5
7
)
Differentiation Rules
Find
d
d
x
(
sin
2
x
+
π
+
cos
2
x
+
5
7
)
\frac{d}{dx}(\sin^2{x}+\sqrt\pi+\cos^2{x}+5^7)
d
x
d
(
sin
2
x
+
π
+
cos
2
x
+
5
7
)
Practice: Equation of Tangent Line
Practice: Equation of Tangent Line
Find the equation of the tangent line to the graph
y
=
sin
x
+
3
x
2
cos
x
y=\sin x+3x^2\cos x
y
=
sin
x
+
3
x
2
cos
x
at the point where
x
=
π
2
x=\frac{\pi}{2}
x
=
2
π
.
Practice: Equation of Tangent Line
Practice: Equation of Tangent Line
Find the equation of the tangent line to the graph
y
=
sin
x
+
3
x
2
cos
x
y=\sin x+3x^2\cos x
y
=
sin
x
+
3
x
2
cos
x
at the point where
x
=
π
2
x=\frac{\pi}{2}
x
=
2
π
.
Practice: Equation of Tangent Line
Practice: Equation of Tangent Line
Find the equation of the tangent line to the graph
y
=
sin
x
+
3
x
2
cos
x
y=\sin x+3x^2\cos x
y
=
sin
x
+
3
x
2
cos
x
at the point where
x
=
π
2
x=\frac{\pi}{2}
x
=
2
π
.
Derivatives: Trigonometric Functions
Find
f
′
(
π
)
+
f
′
′
(
π
)
f'(\pi)+f''(\pi)
f
′
(
π
)
+
f
′′
(
π
)
if
𝑓
(
𝑥
)
=
𝑥
cos
𝑥
−
sin
𝑥
𝑓(𝑥) = 𝑥 \cos 𝑥 − \sin 𝑥
f
(
x
)
=
x
cos
x
−
sin
x
.
Find the equation of the tangent line to the graph
y
=
sin
x
+
3
x
2
cos
x
y=\sin x+3x^2\cos x
y
=
sin
x
+
3
x
2
cos
x
at the point where
x
=
π
2
x=\frac{\pi}{2}
x
=
2
π
.
Practice: Equation of Tangent Line
Practice: Equation of Tangent Line
Find the equation of the tangent line to the graph
y
=
sin
x
+
3
x
2
cos
x
y=\sin x+3x^2\cos x
y
=
sin
x
+
3
x
2
cos
x
at the point where
x
=
π
2
x=\frac{\pi}{2}
x
=
2
π
.
Differentiation Rules
Find
d
d
x
(
sin
2
x
+
π
+
cos
2
x
+
5
7
)
\frac{d}{dx}(\sin^2{x}+\sqrt\pi+\cos^2{x}+5^7)
d
x
d
(
sin
2
x
+
π
+
cos
2
x
+
5
7
)
Differentiation Rules
Find
d
d
x
(
sin
2
x
+
π
+
cos
2
x
+
5
7
)
\frac{d}{dx}(\sin^2{x}+\sqrt\pi+\cos^2{x}+5^7)
d
x
d
(
sin
2
x
+
π
+
cos
2
x
+
5
7
)
Higher Order Trig Derivative
Find
y
23
y^{23}
y
23
given
y
=
sin
x
\displaystyle y=\sin x
y
=
sin
x
Higher Order Derivatives
If
f
(
x
)
=
sin
(
2
x
)
f\left(x\right)=\sin\left(2x\right)
f
(
x
)
=
sin
(
2
x
)
, find
f
(
21
)
(
π
2
)
f^{\left(21\right)}\left(\frac{\pi}{2}\right)
f
(
21
)
(
2
π
)
.
(i.e. find the 21st derivative at the point
π
2
\frac{\pi}{2}
2
π
)
Differentiating functions
Find the derivative of the function
f
(
x
)
=
sin
(
x
)
cos
(
x
)
x
3
f(x) = \frac{\sin(x)\cos(x)}{x^3}
f
(
x
)
=
x
3
sin
(
x
)
cos
(
x
)
You do not need to simplify your answer.
Differentiation Rules
Find
d
d
x
(
sin
2
x
+
π
+
cos
2
x
+
5
7
)
\frac{d}{dx}(\sin^2{x}+\sqrt\pi+\cos^2{x}+5^7)
d
x
d
(
sin
2
x
+
π
+
cos
2
x
+
5
7
)
Finding a derivative: Trigonometric and Exponential Functions
Find the derivative of
cos
4
x
+
x
4
4
x
\cos^4x+\frac{x^4}{4^x}
cos
4
x
+
4
x
x
4
.
Finding a derivative: Trigonometric and Exponential Functions
Find the derivative of
cos
4
x
+
x
4
4
x
\cos^4x+\frac{x^4}{4^x}
cos
4
x
+
4
x
x
4
.
The Chain Rule: Finding a derivative
Find the derivative of
f
(
x
)
=
cos
(
e
2
x
)
f\left(x\right)=\sqrt{\cos\left(e^{2x}\right)}
f
(
x
)
=
cos
(
e
2
x
)
Practice: trig and inverse trig derivatives
Practice: trig and inverse trig derivatives
Find the derivative of the following trigonometric and inverse trigonometric functions:
a)
f
(
x
)
=
arcsin
(
3
x
2
)
f(x)=\arcsin(3x^2)
f
(
x
)
=
arcsin
(
3
x
2
)
Higher Order Derivatives
If
f
(
x
)
=
sin
(
2
x
)
f\left(x\right)=\sin\left(2x\right)
f
(
x
)
=
sin
(
2
x
)
, find
f
(
21
)
(
π
2
)
f^{\left(21\right)}\left(\frac{\pi}{2}\right)
f
(
21
)
(
2
π
)
.
(i.e. find the 21st derivative at the point
π
2
\frac{\pi}{2}
2
π
)
Derivatives: Trigonometric Functions
Find the equation of the tangent line to
f
(
x
)
=
(
x
2
−
2
)
sin
x
+
2
x
cos
x
f(x) = (x^2 - 2) \sin x+2x \cos x
f
(
x
)
=
(
x
2
−
2
)
sin
x
+
2
x
cos
x
at
x
=
π
x = \pi
x
=
π
.
Derivatives: Trigonometric Functions
Find
f
′
(
π
)
+
f
′
′
(
π
)
f'(\pi)+f''(\pi)
f
′
(
π
)
+
f
′′
(
π
)
if
𝑓
(
𝑥
)
=
𝑥
cos
𝑥
−
sin
𝑥
𝑓(𝑥) = 𝑥 \cos 𝑥 − \sin 𝑥
f
(
x
)
=
x
cos
x
−
sin
x
.
Derivatives: Trigonometric Functions
Find the derivative of the following function:
f
(
x
)
=
sin
x
cos
x
+
x
3
f(x)=\sin x\cos x+\sqrt[3]{x}
f
(
x
)
=
sin
x
cos
x
+
3
x
Derivatives: Trigonometric Functions
Given that
𝑓
(
𝑥
)
=
𝑥
sin
𝑥
𝑓(𝑥) = 𝑥\sin 𝑥
f
(
x
)
=
x
sin
x
, find
f
′
(
3
π
2
)
f'\ \left(\dfrac{3\pi}{2}\right)
f
′
(
2
3
π
)
.
Derivatives: Trigonometric Functions
Find the derivative of
g
(
x
)
=
sin
(
π
x
+
1
)
−
cos
(
π
x
+
3
2
)
g\left(x\right)=\sin\left(\pi x+1\right)-\cos\left(\dfrac{\pi x+3}{2}\right)
g
(
x
)
=
sin
(
π
x
+
1
)
−
cos
(
2
π
x
+
3
)
Derivatives: Trigonometric Functions
Find the derivative of
f
(
x
)
=
3
x
2
cos
(
2
x
)
\ f\left(x\right)=3x^2\cos\left(2x\right)
f
(
x
)
=
3
x
2
cos
(
2
x
)
.
Derivatives: Exponential and Trigonometric Functions
Differentiate
y
=
csc
(
1
−
3
5
x
)
y=\csc(1-3^{5\sqrt x})
y
=
csc
(
1
−
3
5
x
)
Product and Chain
Q:
\textbf{Q:}
Q:
Find the derivative of
h
(
θ
)
=
θ
2
−
1
cos
(
3
θ
−
1
)
e
−
5
θ
h(\theta)=\sqrt{\theta^2-1}\cos(3\theta-1)e^{-5\theta}
h
(
θ
)
=
θ
2
−
1
cos
(
3
θ
−
1
)
e
−
5
θ
Practice: Chain Rule with Given Values
Q.
\textbf{Q.}
Q.
Given that
g
(
1
)
=
g
′
(
1
)
=
1
g(1)=g^{\prime}(1)=1
g
(
1
)
=
g
′
(
1
)
=
1
, find
f
′
(
π
/
2
)
f^{\prime}(\pi/2)
f
′
(
π
/2
)
if
f
(
x
)
=
g
(
sin
x
)
x
+
1
\displaystyle f(x)=\frac{\sqrt{g(\sin{x})}}{x+1}
f
(
x
)
=
x
+
1
g
(
sin
x
)
.
Second Derivative with Trig
Find the second derivative for the function
g
(
s
)
=
1
tan
s
+
2
e
s
−
cot
s
cos
s
\displaystyle g(s)=\frac{1}{\tan s} +2e^{s}-\frac{\cot s}{\cos s}
g
(
s
)
=
tan
s
1
+
2
e
s
−
cos
s
cot
s
Higher Order Trig Derivative
Find
y
23
y^{23}
y
23
given
y
=
sin
x
\displaystyle y=\sin x
y
=
sin
x
Quotient with Trig
Find the derivative of
h
(
t
)
=
cos
t
sin
t
(
1
+
cos
t
)
\displaystyle h(t)=\frac{\cos t}{\sin t(1+\cos t)}
h
(
t
)
=
sin
t
(
1
+
cos
t
)
cos
t
Tangent Line with Product Rule
Find the equation of the tangent line to the graph of
𝑦
=
sin
𝑥
+
3
𝑥
2
cos
𝑥
𝑦 = \sin 𝑥 + 3𝑥^2 \cos 𝑥
y
=
sin
x
+
3
x
2
cos
x
at the point where
x
=
π
2
\displaystyle x=\frac{\pi}{2}
x
=
2
π
Product and Chain
Q:
\textbf{Q:}
Q:
Find the derivative of
h
(
θ
)
=
θ
2
−
1
cos
(
3
θ
−
1
)
e
−
5
θ
h(\theta)=\sqrt{\theta^2-1}\cos(3\theta-1)e^{-5\theta}
h
(
θ
)
=
θ
2
−
1
cos
(
3
θ
−
1
)
e
−
5
θ
Derivatives: Trigonometric and Exponential Functions
Calculate the derivative of the following functions.
f
(
x
)
=
e
x
2
sec
(
x
)
\displaystyle f(x)=e^{x^2\text{sec}(x)}
f
(
x
)
=
e
x
2
sec
(
x
)
Find the derivative of the following function.
f
(
x
)
=
x
2
+
1
+
cos
x
\displaystyle f(x)=\sqrt{x^2+1+\cos{x}}
f
(
x
)
=
x
2
+
1
+
cos
x
Derivatives: Trigonometric Functions
Find the slope of the tangent line to the following function at
x
=
π
/
6
:
x=\pi/6:
x
=
π
/6
:
g
(
x
)
=
e
−
1
2
ln
(
sin
x
)
g(x)=e^{-\frac{1}{2}\ln(\sin x)}
g
(
x
)
=
e
−
2
1
l
n
(
s
i
n
x
)
Derivatives: Trigonometric Functions
Given that
g
(
1
)
=
g
′
(
1
)
=
1
g(1)=g'(1)=1
g
(
1
)
=
g
′
(
1
)
=
1
, find
f
′
(
π
/
2
)
if
f
(
x
)
=
g
(
sin
x
)
x
+
1
f'(\pi/2) \text{ if }f(x)=\frac{\sqrt{g(\sin x)}}{x+1}
f
′
(
π
/2
)
if
f
(
x
)
=
x
+
1
g
(
s
i
n
x
)
Derivatives: Trigonometric Functions
Find
d
22
d
x
22
(
−
10
cos
(
x
)
)
\frac{d^{22}}{dx^{22}}(-10\cos(x))
d
x
22
d
22
(
−
10
cos
(
x
))
Derivatives: Trigonometric Functions
Find the equation of the tangent line and the normal line to
f
(
x
)
=
(
x
2
−
2
)
sin
x
+
2
x
cos
x
f(x)=(x^2-2)\sin x+2x\cos x
f
(
x
)
=
(
x
2
−
2
)
sin
x
+
2
x
cos
x
at
x
=
π
x=\pi
x
=
π
Derivatives: Trigonometric and Exponential Functions
Compute the derivative of
f
(
x
)
=
tan
(
e
2
x
)
f(x)=\tan(e^{2x})
f
(
x
)
=
tan
(
e
2
x
)
Derivatives: Trigonometric Functions
Find the equation of the line tangent to the graph of
f
(
x
)
=
x
3
sin
(
π
x
)
f(x)=x^3\sin(\pi x)
f
(
x
)
=
x
3
sin
(
π
x
)
at the point
x
=
2.
x=2.
x
=
2.
Practice: Complicated Chain-Rule
Find an expression for the derivative of the following function:
f
(
x
)
=
cos
(
e
2
x
)
f\left(x\right)=\sqrt{\cos \left(e^{2x}\right)}
f
(
x
)
=
cos
(
e
2
x
)
Practice: Chain Rule
Find the derivative of the following function:
y
=
e
sin
(
x
)
y=e^{\sin(\sqrt{x})}
y
=
e
s
i
n
(
x
)
Practice: Equation of Tangent Line
Practice: Equation of Tangent Line
Find the equation of the tangent line to the graph
y
=
sin
x
+
3
x
2
cos
x
y=\sin x+3x^2\cos x
y
=
sin
x
+
3
x
2
cos
x
at the point where
x
=
π
2
x=\frac{\pi}{2}
x
=
2
π
.
Find the equation of the tangent line of the graph
y
=
e
x
cos
x
y=\frac{e^x}{\cos\ x}
y
=
c
o
s
x
e
x
at the point where 𝑥 = 0.
Derivatives: Trigonometric Functions
Find
f
′
(
π
)
+
f
′
′
(
π
)
f'(\pi)+f''(\pi)
f
′
(
π
)
+
f
′′
(
π
)
if
𝑓
(
𝑥
)
=
𝑥
cos
𝑥
−
sin
𝑥
𝑓(𝑥) = 𝑥 \cos 𝑥 − \sin 𝑥
f
(
x
)
=
x
cos
x
−
sin
x
.
Derivatives: Trigonometric Functions
Find the derivative of the following function:
f
(
x
)
=
sin
x
cos
x
+
x
3
f(x)=\sin x\cos x+\sqrt[3]{x}
f
(
x
)
=
sin
x
cos
x
+
3
x
Derivatives: Trigonometric Functions
Given that
𝑓
(
𝑥
)
=
𝑥
sin
𝑥
𝑓(𝑥) = 𝑥\sin 𝑥
f
(
x
)
=
x
sin
x
, find
f
′
(
3
π
2
)
f'\ \left(\dfrac{3\pi}{2}\right)
f
′
(
2
3
π
)
.
Derivatives: Trigonometric Functions
Find the derivative of
g
(
x
)
=
sin
(
π
x
+
1
)
−
cos
(
π
x
+
3
2
)
g\left(x\right)=\sin\left(\pi x+1\right)-\cos\left(\dfrac{\pi x+3}{2}\right)
g
(
x
)
=
sin
(
π
x
+
1
)
−
cos
(
2
π
x
+
3
)
Derivatives: Trigonometric Functions
Find the equation of the tangent line to
f
(
x
)
=
(
x
2
−
2
)
sin
x
+
2
x
cos
x
f(x) = (x^2 - 2) \sin x+2x \cos x
f
(
x
)
=
(
x
2
−
2
)
sin
x
+
2
x
cos
x
at
x
=
π
x = \pi
x
=
π
.
Practice: Equation of Tangent Line
Practice: Equation of Tangent Line
Find the equation of the tangent line to the graph
y
=
sin
x
+
3
x
2
cos
x
y=\sin x+3x^2\cos x
y
=
sin
x
+
3
x
2
cos
x
at the point where
x
=
π
2
x=\frac{\pi}{2}
x
=
2
π
.
Practice: Equation of Tangent Line
Practice: Equation of Tangent Line
Find the equation of the tangent line to the graph
y
=
sin
x
+
3
x
2
cos
x
y=\sin x+3x^2\cos x
y
=
sin
x
+
3
x
2
cos
x
at the point where
x
=
π
2
x=\frac{\pi}{2}
x
=
2
π
.
Practice: Equation of Tangent Line
Practice: Equation of Tangent Line
Find the equation of the tangent line to the graph
y
=
sin
x
+
3
x
2
cos
x
y=\sin x+3x^2\cos x
y
=
sin
x
+
3
x
2
cos
x
at the point where
x
=
π
2
x=\frac{\pi}{2}
x
=
2
π
.
Derivatives: Trigonometric Functions
Find the derivative of
f
(
x
)
=
3
x
2
cos
(
2
x
)
\ f\left(x\right)=3x^2\cos\left(2x\right)
f
(
x
)
=
3
x
2
cos
(
2
x
)
.
Derivatives: Exponential and Trigonometric Functions
Differentiate
y
=
csc
(
1
−
3
5
x
)
y=\csc(1-3^{5\sqrt x})
y
=
csc
(
1
−
3
5
x
)
Product and Chain
Q:
\textbf{Q:}
Q:
Find the derivative of
h
(
θ
)
=
θ
2
−
1
cos
(
3
θ
−
1
)
e
−
5
θ
h(\theta)=\sqrt{\theta^2-1}\cos(3\theta-1)e^{-5\theta}
h
(
θ
)
=
θ
2
−
1
cos
(
3
θ
−
1
)
e
−
5
θ
Practice: Chain Rule with Given Values
Q.
\textbf{Q.}
Q.
Given that
g
(
1
)
=
g
′
(
1
)
=
1
g(1)=g^{\prime}(1)=1
g
(
1
)
=
g
′
(
1
)
=
1
, find
f
′
(
π
/
2
)
f^{\prime}(\pi/2)
f
′
(
π
/2
)
if
f
(
x
)
=
g
(
sin
x
)
x
+
1
\displaystyle f(x)=\frac{\sqrt{g(\sin{x})}}{x+1}
f
(
x
)
=
x
+
1
g
(
sin
x
)
.
Higher Order Trig Derivative
Find
y
23
y^{23}
y
23
given
y
=
sin
x
\displaystyle y=\sin x
y
=
sin
x
Second Derivative with Trig
Find the second derivative for the function
g
(
s
)
=
1
tan
s
+
2
e
s
−
cot
s
cos
s
\displaystyle g(s)=\frac{1}{\tan s} +2e^{s}-\frac{\cot s}{\cos s}
g
(
s
)
=
tan
s
1
+
2
e
s
−
cos
s
cot
s
Quotient with Trig
Find the derivative of
h
(
t
)
=
cos
t
sin
t
(
1
+
cos
t
)
\displaystyle h(t)=\frac{\cos t}{\sin t(1+\cos t)}
h
(
t
)
=
sin
t
(
1
+
cos
t
)
cos
t
Tangent Line with Product Rule
Find the equation of the tangent line to the graph of
𝑦
=
sin
𝑥
+
3
𝑥
2
cos
𝑥
𝑦 = \sin 𝑥 + 3𝑥^2 \cos 𝑥
y
=
sin
x
+
3
x
2
cos
x
at the point where
x
=
π
2
\displaystyle x=\frac{\pi}{2}
x
=
2
π
Derivatives of Trigonometric Functions
Determine the point(s), if any, where the function
y
=
cos
2
x
−
sin
2
x
y=\cos^2x-\sin^2x
y
=
cos
2
x
−
sin
2
x
has a horizontal tangent line.
Derivatives: Trigonometric and Logarithmic Functions
Find
d
d
y
[
(
y
5
+
ln
y
)
tan
y
]
\displaystyle \frac{\text{d}}{\text{d}y}\left[\left(y^5+\ln y\right)\tan y\right]
d
y
d
[
(
y
5
+
ln
y
)
tan
y
]
.
Derivatives: Trigonometric and Exponential Functions
Evaluate
d
d
x
(
e
x
sin
x
)
\displaystyle \frac{\text{d}}{\text{d}x}\left(e^x\sin x\right)
d
x
d
(
e
x
sin
x
)
.
Find the derivative of the function
f
(
x
)
=
sin
x
cos
x
+
x
3
f(x)=\sin x\cos x+\sqrt[3]{x}
f
(
x
)
=
sin
x
cos
x
+
3
x
.
Find the equation of the tangent line to
f
(
x
)
=
(
x
2
−
2
)
sin
x
+
2
x
cos
x
f(x) = (x^2 - 2) \sin x+2x \cos x
f
(
x
)
=
(
x
2
−
2
)
sin
x
+
2
x
cos
x
at
x
=
π
x = \pi
x
=
π
.
Find the derivative of 𝑓(𝑥) = 𝑒
𝑥
tan 𝑥 + 3.
Given the function
f
(
x
)
=
g
(
x
)
h
(
x
)
−
e
x
cos
x
f\left(x\right)=\frac{g\left(x\right)}{h\left(x\right)}-e^x\cos x
f
(
x
)
=
h
(
x
)
g
(
x
)
−
e
x
cos
x
,
g
(
π
2
)
=
2
g\left(\frac{\pi}{2}\right)=2
g
(
2
π
)
=
2
,
g
′
(
π
2
)
=
3
g'\left(\frac{\pi}{2}\right)=3
g
′
(
2
π
)
=
3
,
h
(
π
2
)
=
1
h\left(\frac{\pi}{2}\right)=1
h
(
2
π
)
=
1
, and
h
′
(
π
2
)
=
2
h'\left(\frac{\pi}{2}\right)=2
h
′
(
2
π
)
=
2
, find
f
′
(
π
2
)
f'\left(\frac{\pi}{2}\right)
f
′
(
2
π
)
.
Finding a derivative: Trigonometric and Exponential Functions
Find the derivative of
cos
4
x
+
x
4
4
x
\cos^4x+\frac{x^4}{4^x}
cos
4
x
+
4
x
x
4
.
Practice: trig and inverse trig derivatives
Practice: trig and inverse trig derivatives
Find the derivative of the following trigonometric and inverse trigonometric functions:
a)
f
(
x
)
=
arcsin
(
3
x
2
)
f(x)=\arcsin(3x^2)
f
(
x
)
=
arcsin
(
3
x
2
)
The Chain Rule: Finding a derivative
Find the derivative of
f
(
x
)
=
cos
(
e
2
x
)
f\left(x\right)=\sqrt{\cos\left(e^{2x}\right)}
f
(
x
)
=
cos
(
e
2
x
)
Higher Order Derivatives
If
f
(
x
)
=
sin
(
2
x
)
f\left(x\right)=\sin\left(2x\right)
f
(
x
)
=
sin
(
2
x
)
, find
f
(
21
)
(
π
2
)
f^{\left(21\right)}\left(\frac{\pi}{2}\right)
f
(
21
)
(
2
π
)
.
(i.e. find the 21st derivative at the point
π
2
\frac{\pi}{2}
2
π
)
Differentiating functions
Find the derivative of the function
f
(
x
)
=
sin
(
x
)
cos
(
x
)
x
3
f(x) = \frac{\sin(x)\cos(x)}{x^3}
f
(
x
)
=
x
3
sin
(
x
)
cos
(
x
)
You do not need to simplify your answer.
Practice: Chain Rule
Find the derivative of the following function:
y
=
sin
(
x
)
y=\sin(\sqrt{x})
y
=
sin
(
x
)
Differentiation Rules
Find
d
d
x
(
sin
2
x
+
π
+
cos
2
x
+
5
7
)
\frac{d}{dx}(\sin^2{x}+\sqrt\pi+\cos^2{x}+5^7)
d
x
d
(
sin
2
x
+
π
+
cos
2
x
+
5
7
)
Derivatives: Trigonometric Functions
Find
f
′
(
π
/
2
)
f^{\prime}(\pi/2)
f
′
(
π
/2
)
if
f
(
x
)
=
g
(
sin
x
)
x
+
1
\displaystyle f(x)=\frac{\sqrt{g(\sin{x})}}{x+1}
f
(
x
)
=
x
+
1
g
(
sin
x
)
, where
g
(
1
)
=
g
′
(
1
)
=
1.
g(1)=g^{\prime}(1)=1.
g
(
1
)
=
g
′
(
1
)
=
1.
Derivatives: Trigonometric Functions
Find the derivative of the following function.
f
(
x
)
=
x
2
+
1
+
cos
x
\displaystyle f(x)=\sqrt{x^2+1+\cos{x}}
f
(
x
)
=
x
2
+
1
+
cos
x
Practice: The Chain Rule
Find the derivative of the following function
y
=
e
sin
x
y=e^{\sin\sqrt{x}}
y
=
e
s
i
n
x
Derivatives: Trigonometric and Exponential Functions
Calculate the derivative of the following functions.
f
(
x
)
=
tan
(
arccos
(
e
4
x
)
)
\displaystyle f(x)=\tan(\text{arccos}(e^{4x}))
f
(
x
)
=
tan
(
arccos
(
e
4
x
))