Antiderivatives: Trigonometric Functions

Evaluate the integral[tan2x+1+1sec2x+sin2x]dx\displaystyle \int_{ }^{ }\left[\tan^2x+1+\frac{1}{\sec^2x}+\sin^2x\right]dx.
Hint: First simplify using trig identities
More Antiderivatives of Trig Functions Questions: