Linear Approximation

Use a suitable linear approximation to estimate 3.99\sqrt{3.99}. Is your estimate likely to be an over- or under-estimate? HINT: Use f(x)=xf(x)=\sqrt{x}, which gives us f(x)=12xf'(x)=\frac1{2\sqrt{x}} and f(x)=14x23f''(x)=-\dfrac{1}{4\sqrt[3]{x^2}}.
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