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Solve the following inequality |2x-3|+|x-4|≥3

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Wize University Calculus 1 Textbook > Pre-Calculus (Review)

Absolute Value Functions

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Solve the following inequality ∣2x−3∣+∣x−4∣≥3\left|2x-3\right|+\left|x-4\right|\ge3
More Absolute Value Functions Questions:
Absolute Value Functions: Function Properties
If f(x)=∣x−2∣, g(x)=3−x+1f\left(x\right)=\left|x-2\right|,\ g\left(x\right)=3-\sqrt{x+1}, which of the following is true about h(x)=g(f(x))h\left(x\right)=g\left(f\left(x\right)\right)?
Solve the following inequality ∣2x−3∣+∣x−4∣≥3\left|2x-3\right|+\left|x-4\right|\ge3
Absolute Value Functions: Inequalities with Absolute Values
Solve the following inequality: ∣x+1∣≥x+42\displaystyle\left|x+1\right|\ge\frac{x+4}{2}
Absolute Value Functions: Inequality with Absolute Values
Find all xx that satisfy the inequality ∣x2−3x+1∣<1\left|x^2−3x+1\right|<1
Absolute Value Functions: Function Properties
If f(x)=∣x−2∣, g(x)=3−x+1f\left(x\right)=\left|x-2\right|,\ g\left(x\right)=3-\sqrt{x+1}, which of the following is true about h(x)=g(f(x))h\left(x\right)=g\left(f\left(x\right)\right)?
Absolute Value Functions
Solve the inequality for xx, ∣3x−4∣+∣x−2∣≥5|3x-4|+|x-2| \geq 5.
Absolute Value Functions: Inequalities with Absolute Values
Solve the following inequality: ∣x+1∣≥x+42\displaystyle\left|x+1\right|\ge\frac{x+4}{2}
Absolute Value Functions: Inequality with Absolute Values
Find all xx that satisfy the inequality ∣x2−3x+1∣<1\left|x^2−3x+1\right|<1