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Find ∫ (√[3]x^2-√[5]x+1/(√[4]x^3))dx
Related Topics
Wize University Calculus 1 Textbook > Integrals
Antiderivatives & The Indefinite Integrals
5 Activities
Find
∫
(
x
2
3
−
x
5
+
1
x
3
4
)
d
x
\displaystyle \int \left(\sqrt[3]{x^2}-\sqrt[5]{x}+\frac{1}{\sqrt[4]{x^3}}\right)dx
∫
(
3
x
2
−
5
x
+
4
x
3
1
)
d
x
5
3
x
5
3
−
6
5
x
6
5
+
4
x
1
4
+
C
\displaystyle\frac{5}{3}x^{\frac{5}{3}}-\frac{6}{5}x^{\frac{6}{5}}+4x^{\frac{1}{4}}+C
3
5
x
3
5
−
5
6
x
5
6
+
4
x
4
1
+
C
3
5
x
2
3
−
5
6
x
1
5
+
4
x
−
1
4
+
C
\displaystyle\frac{3}{5}x^{\frac{2}{3}}-\frac{5}{6}x^{\frac{1}{5}}+4x^{-\frac{1}{4}}+C
5
3
x
3
2
−
6
5
x
5
1
+
4
x
−
4
1
+
C
3
5
x
5
3
−
5
6
x
6
5
+
4
x
1
4
+
C
\displaystyle\frac{3}{5}x^{\frac{5}{3}}-\frac{5}{6}x^{\frac{6}{5}}+4x^{\frac{1}{4}}+C
5
3
x
3
5
−
6
5
x
5
6
+
4
x
4
1
+
C
2
3
x
−
1
3
−
1
5
x
−
4
5
−
3
4
x
−
1
4
+
C
\displaystyle\frac{2}{3}x^{-\frac{1}{3}}-\frac{1}{5}x^{-\frac{4}{5}}-\dfrac{3}{4}x^{-\frac{1}{4}}+C
3
2
x
−
3
1
−
5
1
x
−
5
4
−
4
3
x
−
4
1
+
C
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Check Submission
More Antiderivatives & The Indefinite Integrals Questions:
Practice: Definite Integral
Practice: Definite Integral
Evaluate
∫
−
2
0
∣
x
2
−
1
∣
d
x
\displaystyle \int_{-2}^0\left|x^2-1\right|dx
∫
−
2
0
x
2
−
1
d
x
.
Antiderivatives: Indefinite integrals
Evaluate the integral
∫
1
+
1
x
+
2
x
2
+
3
x
3
d
x
\displaystyle\int_{ }^{ }1+\frac{1}{x}+\frac{2}{x^2}+\frac{3}{x^3}dx
∫
1
+
x
1
+
x
2
2
+
x
3
3
d
x
.
Antiderivatives: Indefinite integrals
Evaluate the integral
∫
1
+
1
x
+
2
x
2
+
3
x
3
d
x
\displaystyle\int_{ }^{ }1+\frac{1}{x}+\frac{2}{x^2}+\frac{3}{x^3}dx
∫
1
+
x
1
+
x
2
2
+
x
3
3
d
x
.
Antiderivatives: Indefinite Integrals
If
F
(
x
)
=
ln
(
2
x
2
)
F(x) = \ln(2x^2)
F
(
x
)
=
ln
(
2
x
2
)
is an antiderivative of
f
(
x
)
f(x)
f
(
x
)
, find
f
f
f
.
Practice: Definite Integral
Practice: Definite Integral
Evaluate
∫
−
2
0
∣
x
2
−
1
∣
d
x
\displaystyle \int_{-2}^0\left|x^2-1\right|dx
∫
−
2
0
x
2
−
1
d
x
.
Find
∫
(
x
2
3
−
x
5
+
1
x
3
4
)
d
x
\displaystyle \int \left(\sqrt[3]{x^2}-\sqrt[5]{x}+\frac{1}{\sqrt[4]{x^3}}\right)dx
∫
(
3
x
2
−
5
x
+
4
x
3
1
)
d
x
Practice: Indefinite Simplify First
Q:
\textbf{Q:}
Q:
Find
∫
[
x
2
−
4
x
x
+
x
(
2
x
2
−
3
x
)
]
d
x
\displaystyle\int_{ }^{ }\left[\frac{x^2-4\sqrt{x}}{\sqrt{x}}+x\left(2x^2-3x\right)\right]dx
∫
[
x
x
2
−
4
x
+
x
(
2
x
2
−
3
x
)
]
d
x
Practice: Indefinite Integral
Evaluate the integral
∫
x
+
1
+
1
x
+
2
x
2
d
x
\displaystyle\int_{ }^{ }x+1+\frac{1}{x}+\frac{2}{x^2}dx
∫
x
+
1
+
x
1
+
x
2
2
d
x
Practice: Indefinite Integral
Evaluate the integral
∫
1
+
1
x
+
2
x
2
+
3
x
3
d
x
\displaystyle\int_{ }^{ }1+\frac{1}{x}+\frac{2}{x^2}+\frac{3}{x^3}dx
∫
1
+
x
1
+
x
2
2
+
x
3
3
d
x
.
Antiderivatives: Exponential Functions
Which of the following is the most general antiderivative of the function
e
3
x
+
7
e^{3x+7}
e
3
x
+
7
? In the functions below,
c
c
c
is an arbitrary constant.
Antiderivatives and Indefinite Integrals
Find the most general antiderivative of
f
(
x
)
=
e
2
f\left(x\right)=e^2
f
(
x
)
=
e
2
Riemann Sums
Evaluate
lim
n
→
∞
∑
i
=
1
n
[
5
n
[
(
1
+
5
i
n
)
2
−
3
]
]
\displaystyle \lim_{n\to\infty}\ \sum_{i=1}^n\left[\frac{5}{n}\left[\left(1+\frac{5i}{n}\right)^2-3\right]\right]
n
→
∞
lim
i
=
1
∑
n
[
n
5
[
(
1
+
n
5
i
)
2
−
3
]
]
Find
∫
x
e
3
d
x
\int_{ }^{ }xe^3\ dx
∫
x
e
3
d
x
Antiderivatives: Indefinite Integrals
If
F
(
x
)
=
ln
(
2
x
2
)
F(x) = \ln(2x^2)
F
(
x
)
=
ln
(
2
x
2
)
is an antiderivative of
f
(
x
)
f(x)
f
(
x
)
, find
f
f
f
.
Antiderivatives: Indefinite Integrals
The graph of an
antiderivative
of
f
(
x
)
f(x)
f
(
x
)
is given below. Graph
f
(
x
)
f(x)
f
(
x
)
.
Find an antiderivative for
f
(
x
)
=
x
5
+
2
x
4
x
\displaystyle f(x)=\frac{x^5+2\sqrt{x}}{4x}
f
(
x
)
=
4
x
x
5
+
2
x
Find an antiderivative for
f
(
x
)
=
x
5
+
2
x
4
x
\displaystyle f(x)=\frac{x^5+2\sqrt{x}}{4x}
f
(
x
)
=
4
x
x
5
+
2
x
Find
∫
l
n
(
e
4
x
)
d
x
\displaystyle \int ln(e^{4x})dx
∫
l
n
(
e
4
x
)
d
x
If
F
(
x
)
=
ln
(
2
x
2
)
F(x)=\ln(2x^2)
F
(
x
)
=
ln
(
2
x
2
)
is an antiderivative of
f
(
x
)
f(x)
f
(
x
)
, find
f
.
Antiderivatives: Indefinite integrals
Evaluate the integral
∫
1
+
1
x
+
2
x
2
+
3
x
3
d
x
\displaystyle\int_{ }^{ }1+\frac{1}{x}+\frac{2}{x^2}+\frac{3}{x^3}dx
∫
1
+
x
1
+
x
2
2
+
x
3
3
d
x
.
Practice: Indefinite Simplify First
Q:
\textbf{Q:}
Q:
Find
∫
[
x
2
−
4
x
x
+
x
(
2
x
2
−
3
x
)
]
d
x
\displaystyle\int_{ }^{ }\left[\frac{x^2-4\sqrt{x}}{\sqrt{x}}+x\left(2x^2-3x\right)\right]dx
∫
[
x
x
2
−
4
x
+
x
(
2
x
2
−
3
x
)
]
d
x
Antiderivatives: Indefinite integrals
Evaluate the indefinite integral
∫
x
2
3
−
x
5
+
1
x
3
4
d
x
\displaystyle \int \sqrt[3]{x^2}-\sqrt[5]{x}+\frac{1}{\sqrt[4]{x^3}}dx
∫
3
x
2
−
5
x
+
4
x
3
1
d
x
.
Indefinite Integrals: Antiderivatives
Find the indefinite integral
∫
2
x
(
2
x
+
3
)
2
d
x
\int2x(2x+3)^2dx
∫
2
x
(
2
x
+
3
)
2
d
x
Find
∫
x
e
3
d
x
\int_{ }^{ }xe^3\ dx
∫
x
e
3
d
x
Antiderivatives: Indefinite Integrals
Find
∫
[
x
2
−
4
x
x
+
x
(
2
x
2
−
3
x
)
]
d
x
\int_{ }^{ }\left[\frac{x^2-4\sqrt{x}}{\sqrt{x}}+x\left(2x^2-3x\right)\right]dx
∫
[
x
x
2
−
4
x
+
x
(
2
x
2
−
3
x
)
]
d
x
.
Practice: Definite Integral
Practice: Definite Integral
Evaluate
∫
−
2
0
∣
x
2
−
1
∣
d
x
\displaystyle \int_{-2}^0\left|x^2-1\right|dx
∫
−
2
0
x
2
−
1
d
x
.
Antiderivatives: Indefinite Integrals
For the following function, find the most general antiderivative.
f
(
x
)
=
x
5
+
2
x
4
x
\displaystyle f(x)=\frac{x^5+2\sqrt{x}}{4x}
f
(
x
)
=
4
x
x
5
+
2
x
Find the antiderivative
F
F
F
f
(
x
)
=
4
x
+
x
2
2
+
5
,
F
(
1
)
=
1
/
3
\displaystyle f(x)=4x+\frac{x^2}{2}+5, F(1)=1/3
f
(
x
)
=
4
x
+
2
x
2
+
5
,
F
(
1
)
=
1/3