If f(4)=1, f'(4)=-1 and g(x)=(f(x))/(x-3) , then find the equation of the tange…

If f(4)=1f(4)=1, f(4)=1f'(4)=-1 and g(x)=f(x)x3g(x)=\frac{f(x)}{x-3} , then find the equation of the tangent line to the curve g(x)g(x) at x=4x=4.
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