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The improper integral ∫_1^94/((x-1)^1/3) dx
Related Topics
Wize University Calculus 2 Textbook > Improper Integrals
Improper Integrals
4 Activities
The improper integral
∫
1
9
4
(
x
−
1
)
1
/
3
d
x
\displaystyle \int_1^9\frac{4}{\left(x-1\right)^{1/3}} \text{d}x
∫
1
9
(
x
−
1
)
1/3
4
d
x
(a) converges and has value 4
(b) converges and has value 8
(c) converges and has value 16
(d) converges and has value 24
(e) diverges
I don't know
Check Submission
More Improper Integrals Questions:
Practice: Improper Type 1
Evaluate
∫
−
∞
1
e
2
x
d
x
{\displaystyle\int^1_{-\infty}}e^{2x}\de{x}
∫
−
∞
1
e
2
x
d
x
, if it converges.
Practice: Improper Type 1
Evaluate
∫
−
∞
1
e
2
x
d
x
{\displaystyle\int^1_{-\infty}}e^{2x}\de{x}
∫
−
∞
1
e
2
x
d
x
, if it converges.
Practice: Improper Type 1
Practice: Improper Type 1
Evaluate
∫
−
∞
1
e
2
x
d
x
{\displaystyle\int^1_{-\infty}}e^{2x}\de{x}
∫
−
∞
1
e
2
x
d
x
, if it converges.
Practice: Improper Type 1
Practice: Improper Type 1
Evaluate
∫
−
∞
1
e
2
x
d
x
{\displaystyle\int^1_{-\infty}}e^{2x}\de{x}
∫
−
∞
1
e
2
x
d
x
, if it converges.
Practice: Improper Integrals
Which of the following improper integrals are convergent?
1.
∫
0
1
1
x
d
x
\int_{_0}^1\frac{1}{x}dx
∫
0
1
x
1
d
x
2.
∫
0
1
1
x
2
d
x
\int_{_0}^1\frac{1}{x^2}dx
∫
0
1
x
2
1
d
x
Evaluate the integral
∫
−
∞
0
e
x
d
x
\displaystyle \int_{-\infty}^0e^x\ \text{d}x
∫
−
∞
0
e
x
d
x
if it converges.
Practice: Improper Type 1
Practice: Improper Type 1
Evaluate
∫
−
∞
1
e
2
x
d
x
{\displaystyle\int^1_{-\infty}}e^{2x}\de{x}
∫
−
∞
1
e
2
x
d
x
, if it converges.
The improper integral
∫
0
4
4
x
x
d
x
\displaystyle \int_0^4\frac{4}{x\sqrt{x}}\text{d}x
∫
0
4
x
x
4
d
x
Determine the value of the integral
∫
−
2
1
−
4
(
x
+
1
)
3
d
x
\displaystyle \int_{-2}^1\frac{-4}{\left(x+1\right)^3}dx
∫
−
2
1
(
x
+
1
)
3
−
4
d
x
.