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$\tkcth{Moved }\bcth{\to} \key{ Mid} \tkco{ S } \tkcth{ch 3 quiz ✓}$ |
Related Topics
Wize High School Algebra II Textbook (Common Core) > Vectors (Extension Topic)
Length of a Vector (Vector Norm)
5 Activities
If
u
⃗
=
<
−
1
,
2
,
0
,
3
>
\vu = \big<-1,2,0,3\big>
u
=
⟨
−
1
,
2
,
0
,
3
⟩
,
v
⃗
=
<
2
,
−
3
,
2
,
1
>
\vv = \big<2, -3, 2, 1\big>
v
=
⟨
2
,
−
3
,
2
,
1
⟩
and
w
⃗
=
<
2
,
1
,
4
,
−
2
>
\vw = \big<2, 1, 4,-2\big>
w
=
⟨
2
,
1
,
4
,
−
2
⟩
, then
∣
∣
v
⃗
−
w
⃗
∣
u
⃗
∣
|\,|\vv-\vw|\vu|
∣
∣
v
−
w
∣
u
∣
is:
29
\sqrt{29}
29
14
\sqrt{14}
14
20
20
20
406
\sqrt{406}
406
I don't know
Check Submission
More Length of a Vector (Vector Norm) Questions:
$\tkcth{Moved }\bcth{\to} \key{ Mid} \tkco{ S } \tkcth{ch 3 quiz ✓}$ |
Let
v
⃗
=
<
1
,
1
,
2
,
−
3
,
1
>
\vv = \rowvecf{1}{1}{2}{-3,\,1}
v
=
⟨
1
,
1
,
2
,
−
3
,
1
⟩
, find all scalars
t
t
t
such that
∣
t
v
⃗
∣
=
4
|t\vv| = 4
∣
t
v
∣
=
4
.