$\tkct{cut from 19.4F}$ Mid $\tkco{ S}$ | 133 - FML 3 - 18.1W e.g. 60.7

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Given the planes
π1:4x3y+z=2\bcb{\pi_1 \, : \, 4x - 3y + z = 2} and π2:x+2y+2z=0\bcb{\pi_2 \, : \, x + 2y + 2z = 0}, and the lines
L1:{x=3t+2y=2t+1z=t, L2:{x=2t+1y=t+1z=t+3, L3:{x=t+3y=tz=2t+1\bcb{L_1 \, : \, \left\{ \begin{matrix} x & = & 3t + 2 \\ y & = & -2t + 1 \\ z & = & t \end{matrix} \right., ~ L_2 \, : \, \left\{ \begin{matrix} x & = & -2t + 1 \\ y & = & t + 1 \\ z & = & t + 3 \end{matrix} \right., ~ L_3 \, : \, \left\{ \begin{matrix} x & = & t + 3 \\ y & = & -t \\ z & = & 2t +1 \end{matrix} \right.},
and the point P1=(1,1,2)\bcb{P_1 = (1,-1,2)}.

Find the intersection of the planes π1\bcb{\pi_1} and π2\bcb{\pi_2}.
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