Practice: Double Integrals in Polar Coordinates (2)

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Double Integration (polar)

2 Activities

Find ∫D∫1+4x2+4y2dA \displaystyle\int_{D}^{}\int_{}^{}\sqrt{1+4x^2+4y^2}dA~∫D​∫​1+4x2+4y2​dA where D is the lower half of x2+y2=16x^2+y^2=16x2+y2=16

Answer

I don't know

More Double Integration (polar) Questions:

Practice: Double Integrals in Polar Coordinates (1)

What is the volume of the region under the sphere x2+y2+z2=9, x^2+y^2+z^2=9,~x2+y2+z2=9, above the plane z=0, z=0,~z=0, and inside  x2+y2=5?~x^2+y^2=5? x2+y2=5?