19.4F_Final_Builder_Ch_2.13_Algebra_SLE_$\tkco{eg22}$_$\key{Final}$_Builder_$\t…

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Given the system of equations:
{2x14x2=14x1+8x2=2 \left\{ \begin{array}{ll} 2x_1 - 4x_2 & = \quad -1 \\ -4x_1 + 8x_2 & = \quad 2 \end{array} \right.

Show that xg=xp+txh\vx_g = \vx_p + t \vx_h, where xp=[120]\vx_p = \colvec{-\frac12}{0} and xh=[21]\vx_h = \colvec{2}{1} is a solution to the system when t=1,2,3t = 1, 2, 3, i.e. show that the vectors:
xg1=[120]+(1)[21]=[321]xg2=[120]+(2)[21]=[722]xg3=[120]+(3)[21]=[1123] \begin{array}{lcl} \vx_{g_{_1}} & = \colvec{-\frac12}{0} + (1) \colvec{2}{1} & = \colvec{\tfrac32}{1} \\[15pt] % \vx_{g_{_2}} & = \colvec{-\frac12}{0} + (2) \colvec{2}{1} & = \colvec{\tfrac72}{2} \\[15pt] % \vx_{g_{_3}} & = \colvec{-\frac12}{0} + (3) \colvec{2}{1} & = \colvec{\tfrac{11}{2}}{3} \end{array}

are all solutions to the given system.
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