Practice Question

The growth rate of a certain species of wild cats at time t years is given by dPdt=kP\frac{dP}{dt}=kP. If we know that the initial population in year 2000 was 500, and that there were double that amount after one and a half years, what is the population of wild cats in the year 2009?

Practice Question

A population is modeled by dPdt=2.5P(1P3500)\frac{dP}{dt}=2.5P\left(1-\frac{P}{3500}\right)
a.) What are the equilibrium solutions?
b.) For what values of P is the population increasing?
c.) For what values of P is the population decreasing?