Wize High School Algebra II Textbook (Common Core) > Exponential Functions

Applications of Exponential Functions (Growth & Decay)

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Applications of Exponential Functions

Compound Interest

A=P(1+in)nt\boxed{A=P\Bigg(1+\dfrac{i}{n}\Bigg)^{nt}} A=Final Amount ($)P=Initial Amount ($)i=Interest raten=Compound periodst=Time elapsed\begin{array}{rcl} A&=&\text{Final Amount (\$)}\\\\ P&=&\text{Initial Amount (\$)}\\\\ i&=&\text{Interest rate}\\\\ n&=&\text{Compound periods}\\\\ t&=&\text{Time elapsed} \end{array}

Exponential Growth, k>1\colorOne{k>1}

P(t)=a(b)kt\boxed{P(t)=a(b)^{kt}} P(t)=Final Valuea=Initial Value ($)b=Growth Ratek=Growth Constantt=Time elapsed\begin{array}{rcl} P(t)&=&\text{Final Value}\\\\ a&=&\text{Initial Value (\$)}\\\\ b&=&\text{Growth Rate}\\\\ k&=&\text{Growth Constant}\\\\ t&=&\text{Time elapsed} \end{array}


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Exponential Decay, k<1\colorOne{k<1}

P(t)=a(b)kt\boxed{P(t)=a(b)^{kt}} P(t)=Final Valuea=Initial Value ($)b=1Decay Ratek=Decay Constantt=Time elapsed\begin{array}{rcl} P(t)&=&\text{Final Value}\\\\ a&=&\text{Initial Value (\$)}\\\\ b&=&1-\text{Decay Rate}\\\\ k&=&\text{Decay Constant}\\\\ t&=&\text{Time elapsed} \end{array}

Richter Scale

I=10R\boxed{I=10^R} I=IntensityR=Richter scale magnitude\begin{array}{rcl} I&=&\text{Intensity}\\\\ R&=&\text{Richter scale magnitude} \end{array}

ph Scale

H+=10pH\boxed{\text{H}^+=-10^{\text{pH}}} H+=Hydrogen Ion ConcentrationpH=pH unit\begin{array}{rcl} \text{H}^+&=&\text{Hydrogen Ion Concentration}\\\\ \text{pH}&=&\text{pH unit} \end{array}

Decibel Scale

I=10dB\boxed{I=10^{dB}} I=IntensitydB=Decibel unit\begin{array}{rcl} I&=&\text{Intensity}\\\\ dB&=&\text{Decibel unit} \end{array}

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Example: Applications of Exponential Functions

Anita invested $4000 into an account that offers 6.25% compounded monthly. How much is in the account after 10 years?
Round all answers to the nearest hundredth.

Let t=10t=10 years.

A(t)=P(1+in)nt=4000(1+0.062512)12(10)=$7460.87\begin{array}{rcl} A(t)&=&P\Big(1+\frac{i}{n}\Big)^{nt}\\\\ &=&4000\Big(1+\frac{0.0625}{12}\Big)^{12(10)}\\\\ &=&\$7460.87 \end{array}

Practice: Applications of Exponential Functions

The half-life of a certain radioactive substance is modelled by the function A(t)=10.4(0.5)t6A(t)=10.4(0.5)^{\frac{t}{6}}, where there is initially 10.4 grams of the substance, the half-life is 6 weeks, and A(t)A(t) is the amount of the substance after tt weeks.

How much of the substance is there after 4 months? Use the fact that there is 4.354.35 weeks in a month.

Practice: Applications of Exponential Functions

The size of a certain species increases five-fold every 3 days. If the size of the population grew to 150000 after 15 days, what was the initial population size?

Practice: Applications of Exponential Functions

The value of a car depreciates roughly 15% annually. Joel buys a new 2021 Honda Civic for $35000 and plans on selling his car again in 10 years. How much will the Honda be worth in 10 years?
Extra Practice