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Using Logarithms to Solve Exponential Equations

When an exponential equation cannot be solved by expressing both sides as the same base, then logarithms can be used to solve for the solution.

Since logarithmic functions are the inverse of exponential functions, logarithms can be used to solve for the exponent.


Example

If 2x=32^x=3, then x is:

2x=3log22x=log23x=log3log2x1.585\begin{array}{rcl} 2^x&=&3\\\\ \log_{2}2^x&=&\log_{2}3\\\\ x&=&\dfrac{\log3}{\log2}\\\\ x&\approx&1.585 \end{array}
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Example: Using Logarithms to Solve Exponential Equations


Solve to the nearest hundredth.

7x+2=417^{x+2}=41


7x+2=41log77x+2=log741x+2=log41log7x0.09\begin{array}{rcl} 7^{x+2}&=&41\\\\ \log_{7}7^{x+2}&=&\log_{7}{41}\\\\ x+2&=&\dfrac{\log{41}}{\log{7}}\\\\ x&\approx&-0.09 \end{array}

Practice: Using Logarithms to Solve Exponential Equations

Solve to the nearest hundredth.

4x+1=5x24^{x+1}=5^{x-2}

Practice: Using Logarithms to Solve Exponential Equations

Find x.

3(2x)=6x23(2^x)=6^{x-2}

Practice: Using Logarithms to Solve Exponential Equations

Solve for x to the nearest hundredth.

4(3x4)=7x4(3^{x-4})=7^x

Extra Practice