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Inverse Functions & Transformations

An inverse function can be defined as a function that reverses another function.
  • f1(x)f^{-1}(x) is the notation used to represent an inverse function
  • f1(x) f^{-1}(x)~ is pronounded "f inverse x"
  • f(x) f(x)~ is reflected over the line y = x to get f1(x)f^{-1}(x)
  • Swap 'x' and 'y' then solve for 'y' to find f1(x)f^{-1}(x)

If two functions, f(x) and g(x), are inverses of each other, then the following two conditions must be true:
  • (fg)(x)=x(f\circ{g})(x)=x
  • (gf)(x)=x(g\circ{f})(x)=x
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Example 1
Let's find and graph f1(x)f^{-1}(x) if f(x)=x2f(x)=x^2

Find f1(x)f^{-1}(x):
Swap x & yx=y2Solve for yy2=xy=±xf1(x)=±x\begin{array}{l c c l} \text{Swap x \& y}&&&x=y^2\\\\ \text{Solve for y}&&&y^2=x\\\\ &&&y=\pm\sqrt{x}\\\\ &&&\therefore f^{-1}(x)=\pm\sqrt{x} \end{array}
Table of values for f(x)=x2f(x)=x^2:
xy2411001124\begin{array}{|c|c|} \hline x&y\\\hline -2&4\\\hline -1&1\\\hline 0&0\\\hline 1&1\\\hline 2&4\\\hline \end{array}
Table of values for f1(x)f^{-1}(x):
xy4211001142\begin{array}{|c|c|} \hline x&y\\\hline 4&-2\\\hline 1&-1\\\hline 0&0\\\hline 1&1\\\hline 4&2\\\hline \end{array}

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Graph of f(x)  vs.  f1(x)f(x)~~vs.~~f^{-1}(x):


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Example 2

Let's show that f(x)=2x1f(x)=2x-1 and g(x)=12x+12g(x)=\frac{1}{2}x+\frac{1}{2} are inversers of each other.

f(g(x))f(g(x)):
f(g(x))=f(12x+12)=2(12x+12)1=x+11=x\begin{array}{l c l} f(g(x))&=&f\Big(\frac{1}{2}x+\frac{1}{2}\Big)\\\\ &=&2\Big(\frac{1}{2}x+\frac{1}{2}\Big)-1\\\\ &=&x+1-1\\\\ &=&x \end{array}
g(f(x))g(f(x)):
g(f(x))=g(2x1)=12(2x1)+12=x12+12=x\begin{array}{l c l} g(f(x))&=&g(2x-1)\\\\ &=&\frac{1}{2}(2x-1)+\frac{1}{2}\\\\ &=&x-\frac{1}{2}+\frac{1}{2}\\\\ &=&x \end{array}
Therefore, f(x) and g(x) are inverses of eachother

Example: Inverse Functions & Transformations

The table of values for y=f(x) y=f(x)~ is shown below:
xy44222163\begin{array}{|c|c|} \hline x&y\\\hline -4&4\\\hline -2&2\\\hline 2&1\\\hline 6&-3\\\hline \end{array}
What is the table of values for the following functions?
  1. y=2f1(2x)+1y=2f^{-1}(2x)+1
  2. y=f1(x1)y=-f^{-1}(-x-1)

Part a.

y=2f1(2x)+1y=2f^{-1}(2x)+1

First, find the table of values for f1(x):f^{-1}(x):
xy44221236\begin{array}{|c|c|} \hline x&y\\\hline 4&-4\\\hline 2&-2\\\hline 1&2\\\hline -3&6\\\hline \end{array}
Then, apply the transformations:
  • Vertical expansion by 2 & 1 unit up
  • Horizontal compression by 12\frac{1}{2}

The table of values for y=2f1(2x)+1y=2f^{-1}(2x)+1:
xy27130.551.513\begin{array}{|c|c|} \hline x&y\\\hline 2&-7\\\hline 1&-3\\\hline 0.5&5\\\hline -1.5&13\\\hline \end{array}

Part b.

y=f1(x1)y=-f^{-1}(-x-1)

First, find the table of values for f1(x)f^{-1}(x):
xy44221236\begin{array}{|c|c|} \hline x&y\\\hline 4&-4\\\hline 2&-2\\\hline 1&2\\\hline -3&6\\\hline \end{array}
Then, apply the transformations:
  • Vertically reflected about the x-axis
  • Horizontally reflected about the y-axis & 1 unit left

The table of values for y=f1(x1)y=-f^{-1}(-x-1):
xy54322226\begin{array}{|c|c|} \hline x&y\\\hline -5&4\\\hline -3&2\\\hline -2&-2\\\hline 2&-6\\\hline \end{array}

Practice: Inverse Functions & Transformations

Let y=f(x) y=f(x)~ be graphed below:

Find and graph f1(x)f^{-1}(x)

Practice: Inverse Functions & Transformations

The function y=f(x) y=f(x)~ is shown below:

Which graph represent y=12f1(2x2)+4y=-\frac{1}{2}f^{-1}(2x-2)+4?

Practice: Inverse Functions & Transformations


If (1, 2) is on the graph of y=3f(2x), y=3f(2x),~ then what point must be on the function y=3f1(2x)?y=3f^{-1}(2x)?
Extra Practice