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Integration by Substitution (a.k.a. "u-Substitution)

It's like "reverse chain rule" for integration.


Identifying Clues

  • If you see a function wrapped up in another function, and its derivative shows up as well
  • If you see both a sin⁡\sin and a cos⁡\cos
  • If you see a ln⁡x\ln x and some xx in the denominator
  • If you see a x\sqrt{x} or 1x\frac{1}{x} wrapped inside another function

Strategy

1. Pick one part of the function and let that be uu

  • u′u' should appear elsewhere in the function
  • Pick uu as the function wrapped inside another
  • Pick uu as ln⁡x\ln x
  • Pick uu as the denominator
  • Sometimes we need to factor or complete the square before we do our u-substitution

2. Differentiate uu → du=...dxdu=...dx


3. Solve for dxdx


4. Substitute uu , replace dxdx

  • For definite integrals, we also want to replace the upper and lower integral bounds with u-bounds
  • If you still have x's remaining in your integral after substitution, go back to your u=...u=... formula and do another substitution


5. Integrate the new function with respect to uu


6. Subsitute the original xx expression back in for uu


Example

Evaluate ∫2xx2−1dx\displaystyle\int_{ }^{ }\frac{2x}{\sqrt{x^2-1}}dx

1. Let u=x2−1u=x^2-1

2. du=2x dxdu=2x\ dx

3. dx=12xdudx=\frac{1}{2x}du

4. ∫2xu(12xdu)\displaystyle \int_{ }^{ }\frac{2x}{\sqrt{u}}\left(\frac{1}{2x}du\right)

=∫1u du=\displaystyle \int \frac{1}{\sqrt{u}}\ du

5. =u1212+C=\frac{u^{\frac{1}{2}}}{\frac{1}{2}}+C

=2u+C=2\sqrt{u}+C

6. 2x2−1+C2\sqrt{x^2-1}+C

Practice: Integration by Substitution

Evaluate ∫e1xx2dx\displaystyle \int_{ }^{ }\frac{e^{\frac{1}{x}}}{x^2}dx

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Example: Integration by Substitution

Evaluate ∫1x+x1/2dx\displaystyle \int_{ }^{ }\frac{1}{x+x^{1/2}}dx


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Practice: Substitution with Definite Integral

Evaluate ∫1e(ln⁡x−5)2xdx\displaystyle \int_1^e\frac{\left(\ln x-5\right)^2}{x}dx.


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Practice: Integration by Substitution (with back-substitution)

Find ∫2x32x2+1dx\int_{ }^{ }\frac{2x^3}{2x^2+1}dx.


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Short-Cut for U-Substitution

Instead of going through the entire process of integration by substitution (u-sub), there is a short-cut for the case where the argument is only changed by a linear term.


Examples

1. ∫cos⁡(2x) dx=\int_{ }^{ }\cos\left(2x\right)\ dx=



2. ∫e−3x dx=\int_{ }^{ }e^{-3x}\ dx=



3. ∫14x−7 dx=\int_{ }^{ }\frac{1}{4x-7}\ dx=