AI TutorHigh School
SAT
ACT
University
MCAT
LSAT
DAT
Wize University Linear Algebra Textbook > Products of Vectors

Cross Product

Projection (Proj) and Perpendicular (Perp)Previous Section
Cross Product PropertiesNext Section
Popular Courses
Find My Course
0:00 / 0:00

Cross Product

We saw that the dot product between two vectors produces a scalar.
Now we introduce the cross product (vector product) of two vectors in R3\reals^3 which produces a vector in R3\bm{\reals^3}.

Definition

The cross product of vectors a⃗=[a1a2a3]\vec{a}= \begin{bmatrix} a_1\\ a_2\\ a_3 \end{bmatrix} and b⃗=[b1b2b3]\vec{b}= \begin{bmatrix} b_1\\ b_2\\ b_3 \end{bmatrix} in R3\reals^3 is
aβƒ—Γ—bβƒ—=[a2b3 βˆ’ a3b2a3b1 βˆ’ a1b3a1b2 βˆ’ a2b1]\boxed{\quad \vec{a}\times\vec{b} = \begin{bmatrix} a_2 b_3 \ βˆ’\ a_3 b_2\\ a_3 b_1 \ βˆ’\ a_1 b_3\\ a_1 b_2 \ βˆ’\ a_2 b_1\\ \end{bmatrix} \quad}

Watch Out!
The cross product only works for vectors in R3\reals^3 (with the exception of a few higher dimensional spaces)

PAGE BREAK

Important Note
The cross product of vectors u⃗\vec u and v⃗\vec v is orthogonal to both u⃗\vec u and v⃗\vec v.

Wize Tip
Use the right hand rule to determine the direction of the vector u⃗×v⃗\vec u \times \vec v:

  1. Point the fingers of your right hand in the direction of u⃗\vec u
  2. Curl your fingers towards v⃗\vec v
  3. u⃗×v⃗\vec u \times \vec v is in the direction your thumb is pointing

PAGE BREAK

Shoelace Method

  1. Copy the column vector a⃗\vec a twice on the left, and b⃗\vec b twice on the right.
  2. Cross out the top and bottom rows, then "lace" the remaining diagonals by multiplying diagonally.
  3. Each diagonal pair makes a single component. Write a minus sign between every pair of products.

Pointing Method

(See video)
0:00 / 0:00

Example: Cross Product

Find a vector that is orthogonal to both uβƒ—=⟨1,βˆ’2,βˆ’1⟩\vec{u}=\lang 1,-2,-1 \rang and vβƒ—=⟨0,3,4⟩\vec{v}=\lang 0,3,4 \rang . Check your answer.

Using the Shoelace Method:

uβƒ—Γ—vβƒ—=[(βˆ’2)(4)  βˆ’  (βˆ’1)(3)(βˆ’1)(0) βˆ’   (1)(4)(1)(3)   βˆ’  (βˆ’2)(0)]=[βˆ’5βˆ’43]\begin{aligned} \vec{u} Γ— \vec{v} &= \begin{bmatrix} (βˆ’2)(4) \ \ βˆ’ \ \ (βˆ’1)(3)\\[0.5em] (βˆ’1)(0)\ βˆ’ \ \ \ (1)(4)\\[0.5em] (1)(3) \ \ \ βˆ’\ \ (βˆ’2)(0)\\ \end{bmatrix}\\[2.5em] &= \boxed{ \begin{bmatrix} -5\\ -4\\ 3\\ \end{bmatrix} } \end{aligned}

Check that this is orthogonal to u⃗\vec u and v⃗\vec v by making sure each dot product is 0:
uβƒ—β‹…(uβƒ—Γ—vβƒ—)=[1βˆ’2βˆ’1]β‹…[βˆ’5βˆ’43]=(1)(βˆ’5)+(βˆ’2)(βˆ’4)+(βˆ’1)(3)=βˆ’5+8βˆ’3=0\begin{aligned} \vec u \cdot (\vec u \times \vec v) &= \begin{bmatrix} 1\\ -2\\ -1\\ \end{bmatrix} \cdot \begin{bmatrix} -5\\ -4\\ 3\\ \end{bmatrix}\\[1.5em] &= (1)(-5) + (-2)(-4) + (-1)(3)\\ &= -5+8-3\\ &= 0 \end{aligned} vβƒ—β‹…(uβƒ—Γ—vβƒ—)=[034]β‹…[βˆ’5βˆ’43]=(0)(βˆ’5)+(3)(βˆ’4)+(4)(3)=0βˆ’12+12=0\begin{aligned} \vec v \cdot (\vec u \times \vec v) &= \begin{bmatrix} 0\\ 3\\ 4\\ \end{bmatrix} \cdot \begin{bmatrix} -5\\ -4\\ 3\\ \end{bmatrix}\\[1.5em] &= (0)(-5) + (3)(-4) + (4)(3)\\ &= 0-12+12\\ &= 0 \end{aligned}

Practice: Orthogonal Vectors

Find a vector orthogonal to both uβƒ—=[2βˆ’13]\vec u = \begin{bmatrix} 2\\ -1\\ 3 \end{bmatrix} and vβƒ—=[0βˆ’1βˆ’1]\vec{v} = \begin{bmatrix} 0\\ -1\\ -1\\ \end{bmatrix}.

For extra practice, check your answer!

Extra Practice
Cross Product
Practice: Orthogonal Vectors
Find a vector orthogonal to both uβƒ—=[2βˆ’13]\vec u = \begin{bmatrix} 2\\ -1\\ 3 \end{bmatrix} and vβƒ—=[0βˆ’1βˆ’1]\vec{v} = \begin{bmatrix} 0\\ -1\\ -1\\ \end{bmatrix}.
For extra practice, check your answer!
Find vec form line thru pt ortho to 2 vec form lines
Find the equation of the line that passes through the point (1,2,βˆ’3)\left(1,2,-3\right) and is orthogonal to the lines with equations:
(x,y,z)=(βˆ’5,0,1)+t(1,0,βˆ’1)(x,y,z)= (-5,0,1)+t(1,0,-1) and (x,y,z)=(3,βˆ’1,6)+t(0,2,1)(x,y,z)=(3,-1,6)+t(0,2,1)
Which of the following vectors is orthogonal to both [1,2,3][1,2,3] and [βˆ’3,1,0][-3,1,0].
Practice Question: Orthogonal Vectors
Practice Question: Orthogonal Vectors
Find a vector orthogonal to both 𝑒⃗=(2,βˆ’1,3)𝑒⃗=(2,βˆ’1,3) and 𝑣⃗=(0,βˆ’1,βˆ’1).\vec{𝑣} = (0, βˆ’1, βˆ’1).
Consider three vectors Aβƒ—=2i^+j^,  Bβƒ—=i^βˆ’2j^\vec{A}=2\hat{i}+\hat{j},\,\,\vec{B}=\hat{i}-2\hat{j}, and Cβƒ—=βˆ’2i^+j^\vec{C}=-2\hat{i}+\hat{j}. The angle between Cβƒ—\vec{C} and Aβƒ—Γ—Bβƒ—\vec{A}\times\vec{B} is?
Evaluate 2k^Γ—(3i^Γ—2j^)2\hat{k}\times(3\hat{i}\times2\hat{j})
Practice: Cross Product
Practice: Cross Product
Recall that iβƒ—=[1, 0, 0]\vec{i}=\left[1,\ 0,\ 0\right], jβƒ—=[0, 1, 0]\vec{j}=\left[0,\ 1,\ 0\right], and kβƒ—=[0, 0, 1]\vec{k}=\left[0,\ 0,\ 1\right].
Match the following cross products with the correct result.
Cross Product
Practice: Orthogonal Vectors
Find a vector orthogonal to both uβƒ—=[2βˆ’13]\vec u = \begin{bmatrix} 2\\ -1\\ 3 \end{bmatrix} and vβƒ—=[0βˆ’1βˆ’1]\vec{v} = \begin{bmatrix} 0\\ -1\\ -1\\ \end{bmatrix}.
For extra practice, check your answer!
Practice Question: Orthogonal Vectors
Practice Question: Orthogonal Vectors
Find a vector orthogonal to both 𝑒⃗=(2,βˆ’1,3)𝑒⃗=(2,βˆ’1,3) and 𝑣⃗=(0,βˆ’1,βˆ’1).\vec{𝑣} = (0, βˆ’1, βˆ’1).
Practice: Orthogonal Vectors
Practice: Orthogonal Vectors
Find a vector orthogonal to both 𝑒⃗=(2,βˆ’1,3)𝑒⃗=(2,βˆ’1,3) and 𝑣⃗=(0,βˆ’1,βˆ’1).\vec{𝑣} = (0, βˆ’1, βˆ’1).
Practice: Cross Product
Practice: Cross Product
Consider uβƒ—=[βˆ’2, 3, βˆ’1]\vec{u}=\left[-2,\ 3,\ -1\right] and vβƒ—=[1, 0, βˆ’1]\vec{v}=\left[1,\ 0,\ -1\right].
If uβƒ—=(2,0,βˆ’3), vβƒ—=(βˆ’2,2,βˆ’4)\vec{u}=\left(2,0,-3\right),\ \vec{v}=\left(-2,2,-4\right) and wβƒ—=(1,2,1)\vec{w}=\left(1,2,1\right), find a vector that is orthogonal to uvβƒ—\vec{uv} and uwβƒ—\vec{uw}.
If 𝑒⃗=(2,0,βˆ’3),𝑣⃗=(βˆ’2,2,βˆ’4),𝑒⃗ = (2, 0, βˆ’3), \vec𝑣 = (βˆ’2, 2, βˆ’4), and 𝑀⃗=(1,2,1)𝑀⃗= (1,2,1), compute uβƒ— Γ— wβƒ—\vec{u}\ \times\ \vec{w}.
Give that 𝑒⃗𝑒⃗ and 𝑣⃗\vec𝑣 are vectors in R3\mathbb{R}^3, which of the following statements is/are always true?
i. 2𝑒⃗+3𝑣⃗=2𝑣⃗+3𝑒⃗2𝑒⃗ + 3\vec𝑣 = 2\vec𝑣 + 3𝑒⃗
ii. 2𝑒⃗.(βˆ’3𝑣⃗)=βˆ’2(3𝑒⃗.𝑣⃗)2𝑒⃗ . (βˆ’3\vec𝑣 ) = βˆ’2(3𝑒⃗ . \vec𝑣 )
If 𝑒⃗=(2,0,βˆ’3),𝑣⃗=(βˆ’2,2,βˆ’4),𝑒⃗ = (2, 0, βˆ’3), \vec𝑣 = (βˆ’2, 2, βˆ’4), and 𝑀⃗=(1,2,1)𝑀⃗= (1,2,1), compute uβƒ— Γ— wβƒ—\vec{u}\ \times\ \vec{w}.
If u=(2,0,βˆ’3), v=(βˆ’2,2,βˆ’4)u=\left(2,0,-3\right),\ v=\left(-2,2,-4\right) and w=(1,2,1)w=\left(1,2,1\right), find a vector that is orthogonal to uvβƒ—\vec{uv} and uwβƒ—\vec{uw}.
Practice Question: Vector Product
Practice Question: Vector Product
Given that 𝑒⃗=(1,1,βˆ’1)𝑒⃗=(1,1,βˆ’1) and 𝑣⃗=(0,βˆ’2,2),𝑣⃗=(0,βˆ’2,2), compute (𝑒⃗⋅𝑣⃗)(𝑣⃗×𝑒⃗).(𝑒⃗\cdot𝑣⃗)(𝑣⃗\times𝑒⃗).
Dot and Cross Products: Vector Norm
If uβƒ—, vβƒ—, wβƒ—  βˆˆ R3\vec{u},\ \vec{v},\ \vec{w}\ \ \in\ R^3, which of the following operations is/are defined?
(i.e. which of the following can be calculated?)
Select all that are correct.