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Practice: Property of Definite Integral

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Wize University Calculus 1 Textbook > Integrals

The Fundamental Theorem of Calculus - Part 2

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Practice: Property of Definite Integral

Given that bothf(x)f\left(x\right) andf′(x)f'\left(x\right) are continuous everywhere, iff(1)=10f\left(1\right)=10 and ∫−31f′(x)dx=12\displaystyle \int_{-3}^1f'\left(x\right)dx=12, find f(−3)f\left(-3\right).

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Given that both f(x)f(x) and f′(x)f'(x) are continuous everywhere, and given f(1)=10f(1)=10 and ∫−31f′(x)dx=12\displaystyle\int_{-3}^1f'\left(x\right)dx=12 , find f(−3)f(-3).
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Practice: Property of Definite Integral
Given that bothf(x)f\left(x\right) andf′(x)f'\left(x\right) are continuous everywhere, iff(1)=10f\left(1\right)=10and ∫−31f′(x)dx=12\int_{-3}^1f'\left(x\right)dx=12, find f(−3)f\left(-3\right).
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Practice: Property of Definite Integral
Given that bothf(x)f\left(x\right) andf′(x)f'\left(x\right) are continuous everywhere, iff(1)=10f\left(1\right)=10and ∫−31f′(x)dx=12\int_{-3}^1f'\left(x\right)dx=12, find f(−3)f\left(-3\right).
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Given that bothf(x)f\left(x\right) andf′(x)f'\left(x\right) are continuous everywhere, iff(1)=10f\left(1\right)=10and ∫−31f′(x)dx=12\displaystyle \int_{-3}^1f'\left(x\right)dx=12, find f(−3)f\left(-3\right).
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Given that both f(x)f(x) and f′(x)f'(x) are continuous everywhere, and given f(1)=10f(1)=10 and ∫−31f′(x)dx=12\displaystyle\int_{-3}^1f'\left(x\right)dx=12 , find f(−3)f(-3).
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Practice: Property of Definite Integral
Practice: Property of Definite Integral
Given that bothf(x)f\left(x\right) andf′(x)f'\left(x\right) are continuous everywhere, iff(1)=10f\left(1\right)=10 and ∫−31f′(x)dx=12\displaystyle \int_{-3}^1f'\left(x\right)dx=12, find f(−3)f\left(-3\right).
Practice: Property of Definite Integral
Practice: Property of Definite Integral
Given that bothf(x)f\left(x\right) andf′(x)f'\left(x\right) are continuous everywhere, iff(1)=10f\left(1\right)=10and ∫−31f′(x)dx=12\int_{-3}^1f'\left(x\right)dx=12, find f(−3)f\left(-3\right).