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Practice: Test of Divergence

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Wize University Calculus 2 Textbook > Sequences and Series

Test of Divergence

5 Activities

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Mark Yourself Question
  1. Grab a piece of paper and try this problem yourself.
  2. When you're done, check the "I have answered this question" box below.
  3. View the solution and report whether you got it right or wrong.

Practice Question

Determine if the series ∑n=1∞nsin⁡1n\sum\limits^\infty_{n=1}n\sin\frac{1}{n} converges or not.

More Test of Divergence Questions:
Practice: Test of Divergence
Determine whether the series ∑n=1∞n3+5n−12n3−7{\displaystyle \sum_{n=1}^\infty}\frac{n^3+5n-1}{2n^3-7} converges or diverges.
Practice: Test of Divergence
Practice Quesetion
Determine whether the series ∑n=1∞n3+5n−12n3−7{\displaystyle \sum_{n=1}^\infty}\frac{n^3+5n-1}{2n^3-7} converges or diverges.
Practice: Test of Divergence
Practice Quesetion
Determine whether the series ∑n=1∞n3+5n−12n3−7{\displaystyle \sum_{n=1}^\infty}\frac{n^3+5n-1}{2n^3-7} converges or diverges.
Practice: Test of Divergence
Practice Question
Determine if the series ∑n=1∞nsin⁡1n\sum\limits^\infty_{n=1}n\sin\frac{1}{n} converges or not.
Practice: Test of Divergence
Practice Quesetion
Determine whether the series ∑n=1∞n3+5n−12n3−7{\displaystyle \sum_{n=1}^\infty}\frac{n^3+5n-1}{2n^3-7} converges or diverges.