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Practice: Test of Divergence
Related Topics
Wize University Calculus 2 Textbook > Sequences and Series
Test of Divergence
5 Activities
Practice Quesetion
Determine whether the series
∑
n
=
1
∞
n
3
+
5
n
−
1
2
n
3
−
7
{\displaystyle \sum_{n=1}^\infty}\frac{n^3+5n-1}{2n^3-7}
n
=
1
∑
∞
2
n
3
−
7
n
3
+
5
n
−
1
converges or diverges.
It converges
It diverges
Cannot be determined
I don't know
Check Submission
More Test of Divergence Questions:
Practice: Test of Divergence
Determine whether the series
∑
n
=
1
∞
n
3
+
5
n
−
1
2
n
3
−
7
{\displaystyle \sum_{n=1}^\infty}\frac{n^3+5n-1}{2n^3-7}
n
=
1
∑
∞
2
n
3
−
7
n
3
+
5
n
−
1
converges or diverges.
Practice: Test of Divergence
Practice Quesetion
Determine whether the series
∑
n
=
1
∞
n
3
+
5
n
−
1
2
n
3
−
7
{\displaystyle \sum_{n=1}^\infty}\frac{n^3+5n-1}{2n^3-7}
n
=
1
∑
∞
2
n
3
−
7
n
3
+
5
n
−
1
converges or diverges.
Practice: Test of Divergence
Practice Question
Determine if the series
∑
n
=
1
∞
n
sin
1
n
\sum\limits^\infty_{n=1}n\sin\frac{1}{n}
n
=
1
∑
∞
n
sin
n
1
converges or not.
Practice: Test of Divergence
Practice Question
Determine if the series
∑
n
=
1
∞
n
sin
1
n
\sum\limits^\infty_{n=1}n\sin\frac{1}{n}
n
=
1
∑
∞
n
sin
n
1
converges or not.
Practice: Test of Divergence
Practice Quesetion
Determine whether the series
∑
n
=
1
∞
n
3
+
5
n
−
1
2
n
3
−
7
{\displaystyle \sum_{n=1}^\infty}\frac{n^3+5n-1}{2n^3-7}
n
=
1
∑
∞
2
n
3
−
7
n
3
+
5
n
−
1
converges or diverges.