Acids and Bases: pH

100 mL100\ mL of a 0.5 M0.5\ M solution of Hydrochloric acid (HCl\rm HCl) was added to 48 mL48\ mL of a 0.410 M0.410\ M solution of sodium benzoate (C6H5COONa\rm C_6H_5COONa) the conjugate base of benzoic acid (C6H5COOH\rm C_6H_5COOH Ka=6.6×105\rm K_a = 6.6 \times 10^{-5}). Calculate the pH\rm pH of the resulting solution.
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