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Autoionization of Water (Kw)

Two water molecules can react with themselves in an autoionization reaction as follows:

2H2O(l)H3O(aq)++OH(aq)2H_2O_{(l)}\leftrightarrow H_3O_{(aq)}^++OH_{(aq)}^-

Kw=[H3O(aq)+][OH(aq)]=1×1014 (25oC)\boxed{K_w=[H_3O_{(aq)}^+][OH_{(aq)}^-]=1\times10^{-14}\ (25^oC)}
Here is the reaction in action!


Photo by Rice University / CC BY

Label whether each reactant and product in the above reaction is acting as an acid/base or conjugate acid/conjugate base.

Water is amphoteric: it can act as an acid or a base!

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Other Key Relationships

Kw = [H+][OH-] = 1x10-14, [H+]= 1x10-7M and [OH-]= 1x10-7M at 25oC

This is why the pH (and pOH) of neutral water is 7

Kw=[H3O(aq)+][OH(aq)]=(Ka)(Kb)=1×1014 (25oC)\boxed{K_w=[H_3O_{(aq)}^+][OH_{(aq)}^-]=(Ka)(Kb)=1\times10^{-14}\ (25^oC)}
*Ka and Kb have to be the K values for an acid and its conjugate base (or a base and its conjugate acid)


If [H+] goes higher, what do you think would happen to [OH-]? Goes higher/lower:
lower


Practice: Solve for [H+]

A solution of HBr has a pOH of 12.2, what is the [H+] concentration?
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Example: pH Problem

If 0.2 mols of HCl(s)\text{HCl}_{(s)} are dissolved in 1.8 L of water, what is the pH?
HCl → H+ + Cl-

Since HCl\text{HCl} is a strong acid, we will be adding 0.2 mols of H+\text{H}^+ to 1.8 L of water.

[H+]=0.2mol1.8L=0.11mol/L[\text{H}^+]=\dfrac{0.2mol}{1.8L}=0.11mol/L

pH=log[H+]=0.95pH=-\log[\text{H}^+]=0.95

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Example: pH Problem

C6H5COOH ⇌ H+ + C6H5COO-

Ka of C6H5COOH = 6.5 x 10-7 and the concentration of C6H5COOH is 0.01 M, what is the pH of the solution?

Write Out An ICE Table

I 0.01M 0 0
C -x +x +x
E 0.01-x x x

Write a K expression and Solve for x

Ka = x²/(0.01 - x) Ka = x²/0.01
We can ignore the "-x" part since y/K > 400

x² = Ka·0.01
x² = (6.5 x 10-7)(0.01) x² = 6.5 x 10-9 x = 8.06 x 10-5
x=[H+]

Find pH

pH = -log[H+] pH = -log(8.06 x 10-5) pH = 4.09



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pH Scale

The pH scale is a logarithmic scale used to measure the concentration of [H+] in a solution, since this value can vary over many orders of magnitude. It ranges from 0 to 14, with 7 representing neutral pH

Note: There are some exceptions to this. For example, an acid could have a negative pH! These aren't commonly seen.

Photo by OpenStax College / CC BY

A lower pH indicates that a substance is more (acidic/basic)
acidic
and has a (higher/lower)
higher
[H+]
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We also have Ka and pKa equations:

pKa=logKa and Ka=10pKapK_a=-\log⁡K_a\ and\ K_a=10^{-pK_a}
As well as Kb and pKb equations:

pKb=logKb and Kb=10pKbpK_b=-\log⁡K_b\ and\ K_b=10^{-pK_b}

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What does it mean to be a logarithmic scale?

How does the [H+] change as the pH goes from 1 to 2 or 1 to 3??



Wize Concept
Since pH is a logarithmic scale, each 1 unit change in pH corresponds to a 10-fold change in [H+]!


Extra Practice