A bacteria population follows the equation y(t)=y_0 e^kt. At time t=3 months, t…

A bacteria population follows the equation y(t)=y0 ekty\left(t\right)=y_0\ e^{kt}. At time t=3t=3 months, the population size is 550550. At time t=6t=6 , the population rises to 13751375. What will the population be after one year? (enter as simplified fraction, do not include any units)
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