Liquification of fuels is an important process that allows fuel to be transport…

Liquification of fuels is an important process that allows fuel to be transported more safely and more easily around the world. Oxidizing methane transforms it from a gas to a liquid, methanol, which is much easier to transport. Using the data provided calculate ΔH\Delta Hfor the oxidation of methane (CH4) shown below
CH4(g) + 1/2 O2(g)CH3OH(l)ΔHfo(CH4(g))=74.9kJ mol1ΔHfo(CH3OH(l)=238.6 kJ mol1\begin{array}{c} CH_{4(g)}\ +\ 1/2\ O_{2(g)} \rightarrow CH_3OH_{(l)} \\ \\ \Delta H^o_f(CH_{4(g)})=-74.9 kJ\ mol^{-1} \\ \Delta H_f^o(CH_3OH_{(l)}=-238.6\ kJ\ mol^{-1} \end{array}

Please report your answer in kJ to four significant figures but do not include the unit. Please include a sign with your answer and report your answer.
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