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Practice: Quotient Rule

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Wize University Calculus 2 Textbook > Review: Derivatives

Derivative Rule

9 Activities

Wize University Calculus 1 Textbook > Derivatives

The Quotient Rule

3 Activities

Find the derivative of f(x)=x2+3x4/3+1x2+1\displaystyle f(x)=\frac{x^2+3x^{4/3}+1}{x^2+1}

More Derivative Rule Questions:
Practice: Derivative Rules (Level 2)
Find the rate of the change of the function f(x)=5x−x32+13x\displaystyle f(x)=\frac{5}{\sqrt{x}}-\frac{\sqrt[3]{x}}{2}+\frac{1}{3x} at the point x=1x=1.
Differentiation Rules
Find ddx(sin⁡2x+π+cos⁡2x+57)\frac{d}{dx}(\sin^2{x}+\sqrt\pi+\cos^2{x}+5^7)
Differentiation Rules
Find ddx(sin⁡2x+π+cos⁡2x+57)\frac{d}{dx}(\sin^2{x}+\sqrt\pi+\cos^2{x}+5^7)
Differentiation Rules
Find ddx(sin⁡2x+π+cos⁡2x+57)\frac{d}{dx}(\sin^2{x}+\sqrt\pi+\cos^2{x}+5^7)
Differentiation Rules
Find ddx(sin⁡2x+π+cos⁡2x+57)\frac{d}{dx}(\sin^2{x}+\sqrt\pi+\cos^2{x}+5^7)
Practice: Product Rule*
Suppose g(x)g\left(x\right) is differentiable, f(x)=x2g(x)f\left(x\right)=x^2g\left(x\right). Given that f′(3)=30f'\left(3\right)=30, f′′(3)=19f''\left(3\right)=19, g(3)=2g\left(3\right)=2, what is g′(3)g'\left(3\right) and g′′(3)g''\left(3\right)?
Practice: Derivative Rule (Level 3)
Practice: Derivative Rule
Given f(t)=2t3(t+1t)t\displaystyle f(t)=\frac{2t^3\left(t+\frac{1}{t}\right)}{\sqrt{t}}, find f′(4)f'\left(4\right).
Differentiation Rules
Find ddx(sin⁡2x+π+cos⁡2x+57)\frac{d}{dx}(\sin^2{x}+\sqrt\pi+\cos^2{x}+5^7)
Practice: Multiple Chain Rules
Practice: Multiple Chain Rules
Find the derivative of f(x)=x+x4+x3+x2+1f\left(x\right)=x+\sqrt{x^4+\sqrt{x^3+\sqrt{x^2+1}}} at x=0x=0
Practice: Derivative Rules (Level 2)
Practice: Derivative Rules
Find the rate of the change of the function f(x)=5x−x32+13x\displaystyle f(x)=\frac{5}{\sqrt{x}}-\frac{\sqrt[3]{x}}{2}+\frac{1}{3x} at the point x=1x=1.
More The Quotient Rule Questions:
Derivatives
Find the derivative of the following functions at the given values
a) f(x)=arcsin⁡(x2)x3−1f\left(x\right)=\frac{\arcsin\left(x^2\right)}{x^3-1} at x=0x=0
b) g(x)=(cos⁡x)exg\left(x\right)=\left(\cos x\right)^{e^x} at x=0x=0
The quotient rule
Is u′(t)=2(t−1)3(−3t+23)(3t+7)7\displaystyle u'\left(t\right)=\frac{2\left(t-1\right)^3\left(-3t+23\right)}{\left(3t+7\right)^7} the derivative of u(t)=(t−1)4(3t+7)6\displaystyle u\left(t\right)=\frac{\left(t-1\right)^4}{\left(3t+7\right)^6} ?
The quotient rule
Find the derivative of the following function:
g(x)=x+1x+1\displaystyle g(x)=\frac{\sqrt{x+1}}{\sqrt{x}+1}
The quotient rule
Is u′(t)=2(t−1)3(−3t+23)(3t+7)7\displaystyle u'\left(t\right)=\frac{2\left(t-1\right)^3\left(-3t+23\right)}{\left(3t+7\right)^7} the derivative of u(t)=(t−1)4(3t+7)6\displaystyle u\left(t\right)=\frac{\left(t-1\right)^4}{\left(3t+7\right)^6} ?
The quotient rule
Given the function f(x)=g(x)h(x)−excos⁡xf\left(x\right)=\dfrac{g\left(x\right)}{h\left(x\right)}-e^x\cos x, and given g(π2)=2g\left(\dfrac{\pi}{2}\right)=2, g′(π2)=3g'\left(\dfrac{\pi}{2}\right)=3, h(π2)=1h\left(\dfrac{\pi}{2}\right)=1, and h′(π2)=2h'\left(\dfrac{\pi}{2}\right)=2, find f′(π2)f'\left(\dfrac{\pi}{2}\right).
Derivatives: Exponential and Logarithmic Functions
Find f′(x)f'(x) if f(x)=ln⁡xxex\displaystyle f\left(x\right)=\frac{\ln x}{xe^{x}}. Simplify.
Quotient and Product
Find the derivative of g(t)=(1+2t7t)(t2−1)\displaystyle g(t)=\left(\frac{1+2t}{7t}\right)(t^{2}-1)
Practice: Quotient Rule
Q.\textbf{Q.} Find the derivative of f(x)=x2+3x4/3+1x2+1\displaystyle f(x)=\frac{x^2+3x^{4/3}+1}{x^2+1}
Find the derivative of the following function:
g(x)=x+1x+1\displaystyle g(x)=\frac{\sqrt{x+1}}{\sqrt{x}+1}
The Quotient and Chain Rules
Let f(x)=x2−6x−3\displaystyle f(x) = \frac{\sqrt{x^2 - 6}}{x - 3}.
The Quotient Rule
Find the derivative of g(x)=x2−52x+1g(x) = \frac{x^2 - 5}{2x + 1}
Derivatives
Find the derivative of the following functions at the given values
a) f(x)=arcsin⁡(x2)x3−1f\left(x\right)=\frac{\arcsin\left(x^2\right)}{x^3-1} at x=0x=0
b) g(x)=(cos⁡x)exg\left(x\right)=\left(\cos x\right)^{e^x} at x=0x=0
The Quotient Rule
Compute the derivative of
f(x)=x2+3x4/3+1x2+1f(x)=\frac{x^2+3x^{4/3}+1}{x^2+1}
Practice: Product Rule*
Suppose g(x)g\left(x\right) is differentiable, f(x)=1+x g(x)x2f\left(x\right)=\frac{1+x\ g\left(x\right)}{x^2}, f′(1)=2f'\left(1\right)=2, g(1)=1g\left(1\right)=1, what is g′(1)g'\left(1\right)?
The quotient rule
Given the function f(x)=g(x)h(x)−excos⁡xf\left(x\right)=\dfrac{g\left(x\right)}{h\left(x\right)}-e^x\cos x, and given g(π2)=2g\left(\dfrac{\pi}{2}\right)=2, g′(π2)=3g'\left(\dfrac{\pi}{2}\right)=3, h(π2)=1h\left(\dfrac{\pi}{2}\right)=1, and h′(π2)=2h'\left(\dfrac{\pi}{2}\right)=2, find f′(π2)f'\left(\dfrac{\pi}{2}\right).
Derivatives: Exponential and Logarithmic Functions
Find f′(x)f'(x) if f(x)=ln⁡xxex\displaystyle f\left(x\right)=\frac{\ln x}{xe^{x}}. Simplify.
The quotient rule
Is u′(t)=2(t−1)3(−3t+23)(3t+7)7\displaystyle u'\left(t\right)=\frac{2\left(t-1\right)^3\left(-3t+23\right)}{\left(3t+7\right)^7} the derivative of u(t)=(t−1)4(3t+7)6\displaystyle u\left(t\right)=\frac{\left(t-1\right)^4}{\left(3t+7\right)^6} ?
Quotient and Product
Find the derivative of g(t)=(1+2t7t)(t2−1)\displaystyle g(t)=\left(\frac{1+2t}{7t}\right)(t^{2}-1)
The Quotient Rule
If h(x)=f(x)−1x+2h\left(x\right)=\frac{f\left(x\right)-1}{x+2}, f(3)=2 and f′(3)=−6f\left(3\right)=2\ \text{and}\ f'\left(3\right)=-6, calculate the value of h′(3)h'\left(3\right)
The Quotient Rule
Is u′(t)=2(t−1)3(−3t+23)(3t+7)7u'\left(t\right)=\frac{2\left(t-1\right)^3\left(-3t+23\right)}{\left(3t+7\right)^7} the derivative of u(t)=(t−1)4(3t+7)6u\left(t\right)=\frac{\left(t-1\right)^4}{\left(3t+7\right)^6} ?
Find the derivative with respect to xx of the function x20303+x2030\displaystyle \frac{x^{2030}}{3+x^{2030}}.
Compute the derivative of f(x)=x2+3x4/3+1x2+1f(x) =\dfrac{x^2 + 3x^{4/3} + 1}{x^2 + 1}.
The Quotient Rule
Suppose g(x)g\left(x\right) is differentiable, f(x)=1+x g(x)x2f\left(x\right)=\frac{1+x\ g\left(x\right)}{x^2}, f′(1)=2f'\left(1\right)=2, g(1)=1g\left(1\right)=1, what is g′(1)g'\left(1\right)?
Find the derivative of the following function:
g(x)=x+1x+1\displaystyle g(x)=\frac{\sqrt{x+1}}{\sqrt{x}+1}
The quotient rule
Find the derivative of the following function:
g(x)=x+1x+1\displaystyle g(x)=\frac{\sqrt{x+1}}{\sqrt{x}+1}