133 - FML 1 - 18.1W e.g. 10.1

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A square n × n matrix AA is said to be diagonalizable if it is similar to a diagonal matrix, i.e. A=P ⁣D ⁣P ⁣1\A = \P \bct{\D} \P^{\bct{-1}} .

Rearranging, we have the definition that A\A is diagonlizable if D ⁣=P ⁣1AP ⁣\D=\P^{\bct{-1}} \A \P is diagonal.

The notation itself should make clear that this is only possible if there is an n×nn\times n matrix P ⁣\P that is invertible (i.e.   P ⁣1  :  P ⁣P ⁣1  =  I ⁣\exist \; \minv{\P} \; : \; \P\minv{\P} \; = \;\I). The question then arises: what is P ⁣\P and how can we find it?


  • e.g. For an n×nn\times n matrix A\A, assume P ⁣\P is an n×nn\times n invertible matrix, and D ⁣= diag(λ1,λ2,λ3,,λn)\D = \text{ diag}(\lambda_1 , \lambda_2 , \lambda_3 , \ldots, \lambda_n ). Without assuming anything else, use the definition of diagonalizability (viz. A=P ⁣D ⁣P ⁣1\A = \P \D \minv{\P} ) to find a necessary and sufficient condition for defining the matrix P ⁣\P by completing the following steps:

  1. Right-multiply the definition for diagonalizability by P ⁣\P:
  2. Let xi{\vx}_{\bco{i}} be the ith\bco{i}^{th} column of the matrix P ⁣\P, then P ⁣=\P=
  3. Using your understanding of the nature of matrix multiplication in general, as well as the special case of right-multiplication of a matrix by a diagonal matrix, use the above representation of P ⁣\P to find column representations of AP ⁣\A\P and P ⁣D ⁣\P \D.






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