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Wize University Physics Textbook (Master) > Heat and Temperature

Calorimetry

4 Activities

A copper sphere with a radius of 5𝑐𝑚 𝑎𝑡 𝑇 = 80℃ is placed into a 2 kg steel vessel which is full of water and ice.
a. What is the final temperature of the system if the final radius of the
copper sphere is 4.996cm?

b. Now assume that only 1/3 of the initial ice-water mixture in the steel vessel is water, how
much ice is melted in this process?

Cw=4190Jkg⋅KLf=334×103Jkg⋅KCst=470Jkg⋅KCcu=390Jkg⋅Kρcu=9gcm3αcu=1.7×10−5\begin{array}{cc}C_{w}=4190\frac{J}{kg\cdot K}&L_{f}=334\times 10^{3}\frac{J}{kg\cdot K}\\C_{st}=470\frac{J}{kg\cdot K}&C_{cu}=390\frac{J}{kg\cdot K}\\\rho_{cu}=9\frac{g}{cm^3 }&\alpha_{cu}=1.7\times 10^{-5}\end{array}
Question A
More Calorimetry Questions:
Calorimetry
Answer the following questions:
Practice: Calorimetry Part 1
Practice: Calorimetry
Answer the following questions.
A solution of ice water that weighs 1 kg1\ kg is mixed with 1 kg1\ kg of water at 100°C100\degree C. After mixing the temperature of the final solution is at 24°C24\degree C. How much of the ice water solution was ice.
Latent heat of ice: 334 Jg334\ \frac{J}{g}
C value for water: 4.186 Jg4.186\ \frac{J}{g}
Liquid helium is stored at its boiling point, 4.2 K4.2\ K, in a spherical capsule that is separated by a vacuum space from a surrounding container that is maintained at the temperature of liquid nitrogen, 77 K77\ K. The capsule has a radius of 0.1 m0.1\ m and it is blackened on the outside.
a) Calculate the amount of helium that boils away in one day.
b) Now imagine the vacuum is replaced by a 20 cm20\ cm glass layer around the spherical capsule. How much helium boils away per day in this new condition?
A copper sphere with a radius of 5 cm5\ cm at T=80°CT=80\degree C is placed into a 2 kg2\ kg steel vessel which is full of water and ice.
What is the final temperature of the system if the final radius of the copper sphere is 4.996 cm4.996\ cm?
If 1/3 of the initial ice-water mixture in the steel vessel is water, how much ice is melted in this process?(gr)
A compound bar made up of 15 cm15\ cm of Cu with Acu=25 cm2A_{cu}=25\ cm^2 and 20 cm20\ cm of steel with ASt=10 cm2A_{St}=10\ cm^2 and T=293 KT=293\ K is fixed at both ends as shown in the diagram below. How much is the stress in each metal if the system is heated uniformly by a 700 watt700\ watt heater for 5 minutes?
CCu=390 Jkg⋅KCSt=470 Jkg⋅KYCu=11×1010 Nm2YSt=20×1010 Nm2αCu=1.7×10−51KαSt=1.2×10−51KρCu=9 kg/cm3ρSt=7.85 kg/cm3\begin{aligned} C_{Cu}=390\ \frac{J}{kg\cdot K} && C_{St}=470\ \frac{J}{kg\cdot K}\\ Y_{Cu}=11\times10^{10}\ \frac{N}{m^2} && Y_{St}=20\times10^{10}\ \frac{N}{m^2}\\ \alpha_{Cu}=1.7\times10^{-5} \frac{1}{K} && \alpha_{St}=1.2 \times10^{-5} \frac{1}{K}\\ \rho_{Cu}=9\ kg/cm^3 && \rho_{St}=7.85\ kg/cm^3 \end{aligned}
Two liters of juice at 20ºC is put in the fridge to cool. How much energy must be removed from the juice to cool it to 8ºC?
When 500g of copper (c=4190 J/kg kc=4190\ J/kg\ k), at 80ºC is added to 500g of water at 10ºC, what is the resulting temperature of the mixture?
Two ice cubes, each of 3.0g are added to lukewarm bottle of water at 7ºC. How much of the ice’s mass will melt? (Lf=333×103 j/kg,L_f=333\times10^3\ j/kg, and 4190 j/kg k4190\ j/kg \ k).
Calorimetry
Answer the following questions:
Practice: Calorimetry Part 2
Part 2
What happens if we add two 20 g20\ g ice cubes at −10°C-10\degree C into the same glass we had in part I. What is temperature at equilibrium? (temperature is in degrees of Celcius)
Cw=4190JKg⋅K, Ci=2100JKg⋅K, Li=334×103JkgC_w=4190\dfrac{J}{Kg\cdot K},\ C_i=2100\dfrac{J}{Kg\cdot K},\ L_i=334\times10^3\dfrac{J}{kg}
The following diagram shows the heating process of 200 g200\ g of an unknown substance at constant rate. The substance is solid at 20°C20\degree C. (Csolid=1300Jkg⋅KC_{solid}=1300 \frac{J}{kg\cdot K})
What is the power of heating?
What is the heat of fusion of this substance?
Practice: Calorimetry Part 3
Part 3
How much ice is left in the glass when the system in part 2 is at thermal equilibrium?
Cw=4190JKg⋅K, Ci=2100JKg⋅K, Li=334×103JkgC_w=4190\dfrac{J}{Kg\cdot K},\ C_i=2100\dfrac{J}{Kg\cdot K},\ L_i=334\times10^3\dfrac{J}{kg}
A copper rod in the form of a cylinder of radius 1cm and length of 1m is heated to 600°C and dropped into 2.00 kg of water at 20.0°C. Assuming that no energy is lost by heat to the surroundings, determine the final equilibrium temperature of the system.
density of Cu = 8.94g/cm3 c(Cu)=385 J/(kgC) c(water)=4182 J/(kgC)