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Calorimetry
Related Topics
Wize University Physics Textbook (Master) > Heat and Temperature
Calorimetry
4 Activities
Answer the following questions:
Part 1
Part 2
Part 3
Part 1
If we add one
20
g
20\ g
20
g
ice cube at
−
10
°
C
−10\degree C
−
10°
C
into a glass with
100
g
100\ g
100
g
of water at
20
°
C
20\degree C
20°
C
, what is the final temperature at thermal equilibrium? (in degrees of Celcius)
C
w
=
4190
J
K
g
⋅
K
,
C
i
=
2100
J
K
g
⋅
K
,
L
i
=
334
×
10
3
J
k
g
C_w=4190\dfrac{J}{Kg\cdot K},\ C_i=2100\dfrac{J}{Kg\cdot K},\ L_i=334\times10^3\dfrac{J}{kg}
C
w
=
4190
K
g
⋅
K
J
,
C
i
=
2100
K
g
⋅
K
J
,
L
i
=
334
×
1
0
3
k
g
J
-2.5
2.55
6.7
I don't know
Previous Part
Check Part 1
Next Part
Check Submission
More Calorimetry Questions:
Calorimetry
Answer the following questions:
Practice: Calorimetry Part 1
Practice: Calorimetry
Answer the following questions.
A solution of ice water that weighs
1
k
g
1\ kg
1
k
g
is mixed with
1
k
g
1\ kg
1
k
g
of water at
100
°
C
100\degree C
100°
C
. After mixing the temperature of the final solution is at
24
°
C
24\degree C
24°
C
. How much of the ice water solution was ice.
Latent heat of ice:
334
J
g
334\ \frac{J}{g}
334
g
J
C value for water:
4.186
J
g
4.186\ \frac{J}{g}
4.186
g
J
Liquid helium is stored at its boiling point,
4.2
K
4.2\ K
4.2
K
, in a spherical capsule that is separated by a vacuum space from a surrounding container that is maintained at the temperature of liquid nitrogen,
77
K
77\ K
77
K
. The capsule has a radius of
0.1
m
0.1\ m
0.1
m
and it is blackened on the outside.
a) Calculate the amount of helium that boils away in one day.
b) Now imagine the vacuum is replaced by a
20
c
m
20\ cm
20
c
m
glass layer around the spherical capsule. How much helium boils away per day in this new condition?
A copper sphere with a radius of
5
c
m
5\ cm
5
c
m
at
T
=
80
°
C
T=80\degree C
T
=
80°
C
is placed into a
2
k
g
2\ kg
2
k
g
steel vessel which is full of water and ice.
What is the final temperature of the system if the final radius of the copper sphere is
4.996
c
m
4.996\ cm
4.996
c
m
?
If 1/3 of the initial ice-water mixture in the steel vessel is water, how much ice is melted in this process?(gr)
A compound bar made up of
15
c
m
15\ cm
15
c
m
of Cu with
A
c
u
=
25
c
m
2
A_{cu}=25\ cm^2
A
c
u
=
25
c
m
2
and
20
c
m
20\ cm
20
c
m
of steel with
A
S
t
=
10
c
m
2
A_{St}=10\ cm^2
A
S
t
=
10
c
m
2
and
T
=
293
K
T=293\ K
T
=
293
K
is fixed at both ends as shown in the diagram below. How much is the stress in each metal if the system is heated uniformly by a
700
w
a
t
t
700\ watt
700
w
a
tt
heater for 5 minutes?
C
C
u
=
390
J
k
g
⋅
K
C
S
t
=
470
J
k
g
⋅
K
Y
C
u
=
11
×
10
10
N
m
2
Y
S
t
=
20
×
10
10
N
m
2
α
C
u
=
1.7
×
10
−
5
1
K
α
S
t
=
1.2
×
10
−
5
1
K
ρ
C
u
=
9
k
g
/
c
m
3
ρ
S
t
=
7.85
k
g
/
c
m
3
\begin{aligned} C_{Cu}=390\ \frac{J}{kg\cdot K} && C_{St}=470\ \frac{J}{kg\cdot K}\\ Y_{Cu}=11\times10^{10}\ \frac{N}{m^2} && Y_{St}=20\times10^{10}\ \frac{N}{m^2}\\ \alpha_{Cu}=1.7\times10^{-5} \frac{1}{K} && \alpha_{St}=1.2 \times10^{-5} \frac{1}{K}\\ \rho_{Cu}=9\ kg/cm^3 && \rho_{St}=7.85\ kg/cm^3 \end{aligned}
C
C
u
=
390
k
g
⋅
K
J
Y
C
u
=
11
×
1
0
10
m
2
N
α
C
u
=
1.7
×
1
0
−
5
K
1
ρ
C
u
=
9
k
g
/
c
m
3
C
S
t
=
470
k
g
⋅
K
J
Y
S
t
=
20
×
1
0
10
m
2
N
α
S
t
=
1.2
×
1
0
−
5
K
1
ρ
S
t
=
7.85
k
g
/
c
m
3
Two liters of juice at 20ºC is put in the fridge to cool. How much energy must be removed from the juice to cool it to 8ºC?
When 500g of copper (
c
=
4190
J
/
k
g
k
c=4190\ J/kg\ k
c
=
4190
J
/
k
g
k
), at 80ºC is added to 500g of water at 10ºC, what is the resulting temperature of the mixture?
Two ice cubes, each of 3.0g are added to lukewarm bottle of water at 7ºC. How much of the ice’s mass will melt? (
L
f
=
333
×
10
3
j
/
k
g
,
L_f=333\times10^3\ j/kg,
L
f
=
333
×
1
0
3
j
/
k
g
,
and
4190
j
/
k
g
k
4190\ j/kg \ k
4190
j
/
k
g
k
).
Practice: Calorimetry Part 2
Part 2
What happens if we add two
20
g
20\ g
20
g
ice cubes at
−
10
°
C
-10\degree C
−
10°
C
into the same glass we had in part I. What is temperature at equilibrium? (temperature is in degrees of Celcius)
C
w
=
4190
J
K
g
⋅
K
,
C
i
=
2100
J
K
g
⋅
K
,
L
i
=
334
×
10
3
J
k
g
C_w=4190\dfrac{J}{Kg\cdot K},\ C_i=2100\dfrac{J}{Kg\cdot K},\ L_i=334\times10^3\dfrac{J}{kg}
C
w
=
4190
K
g
⋅
K
J
,
C
i
=
2100
K
g
⋅
K
J
,
L
i
=
334
×
1
0
3
k
g
J
The following diagram shows the heating process of
200
g
200\ g
200
g
of an unknown substance at constant rate. The substance is solid at
20
°
C
20\degree C
20°
C
. (
C
s
o
l
i
d
=
1300
J
k
g
⋅
K
C_{solid}=1300 \frac{J}{kg\cdot K}
C
so
l
i
d
=
1300
k
g
⋅
K
J
)
What is the power of heating?
What is the heat of fusion of this substance?
Practice: Calorimetry Part 3
Part 3
How much ice is left in the glass when the system in part 2 is at thermal equilibrium?
C
w
=
4190
J
K
g
⋅
K
,
C
i
=
2100
J
K
g
⋅
K
,
L
i
=
334
×
10
3
J
k
g
C_w=4190\dfrac{J}{Kg\cdot K},\ C_i=2100\dfrac{J}{Kg\cdot K},\ L_i=334\times10^3\dfrac{J}{kg}
C
w
=
4190
K
g
⋅
K
J
,
C
i
=
2100
K
g
⋅
K
J
,
L
i
=
334
×
1
0
3
k
g
J
New Practice Question
A copper sphere with a radius of 5𝑐𝑚 𝑎𝑡 𝑇 = 80℃ is placed into a 2 kg steel vessel which is full of water and ice.
a. What is the final temperature of the system if the final radius of the
copper sphere is 4.996cm?
A copper rod in the form of a cylinder of radius 1cm and length of 1m is heated to 600°C and dropped into 2.00 kg of water at 20.0°C. Assuming that no energy is lost by heat to the surroundings, determine the final equilibrium temperature of the system.
density of Cu = 8.94g/cm
3
c(Cu)=385 J/(kgC)
c(water)=4182 J/(kgC)