Thermochemistry: Calorimetry

checklist
Mark Yourself Question
  1. Grab a piece of paper and try this problem yourself.
  2. When you're done, check the "I have answered this question" box below.
  3. View the solution and report whether you got it right or wrong.
Consider the following balanced chemical equation:
2CF3(g)+2O2(g)C2O(g)+3F2O(g)rH°=???2 CℓF_3(g) + 2 O_2(g) → Cℓ_2O (g) + 3 F_2O (g) \qquad ∆_rH° = ???
SubstancefH° @ 25°C (kJ/mol)CF3(g)??C2O(g)80.3F2O(g)21.7F2(g)0\def\arraystretch{1.5} \begin{array}{|c|c|} \hline \rm Substance & △_fH° \ @ \ 25°C \ (kJ/mol) \\ \hline CℓF_3 (g) & ?? \\ \hline Cℓ_2O (g) & 80.3 \\ \hline F_2O (g) & – 21.7 \\ \hline F_2 (g) & 0 \\ \hline \end{array}
(a) Use the data provided for these three reactions at 25°C to calculate the enthalpy change for the reaction above.

Reaction 1: 2CF(g)+O2(g)C2O(g)+F2O(g)rH°=167.4kJ/(molrxn)Reaction 2: CF(g)+F2(g)CF3(g)rH°=108.7kJ/(molrxn)Reaction 3: 2F2(g)+O2(g)2F2O(g)rH°=43.4kJ/(molrxn)\def\arraystretch{1.5} \begin{array}{ccc} &\text{Reaction 1}: &\ 2 CℓF (g) + O_2(g) → Cℓ_2O (g) + F_2O (g) & \qquad ∆_rH° = 167.4 kJ/(mol·rxn) \\ &\text{Reaction 2}: &\ CℓF (g) + F_2 (g) → CℓF_3 (g) & \qquad ∆_rH° = – 108.7 kJ/(mol·rxn) \\ &\text{Reaction 3}: &\ 2 F_2 (g) + O_2 (g) → 2 F_2O (g) & \qquad ∆_rH° = – 43.4 kJ/(mol·rxn) \\ \end{array}

(b) Given your answer to part (a) and (c) and the data below to calculate the value of the standard molar enthalpy of formation fH°) for gaseous CℓF3 (g) at 25°C.

(c) Given the information in the previous parts, explain why the standard formation enthalpy ΔfH° for F2O (g) is exactly half of the reaction enthalpy for Reaction 3 at 25°C.
More Calorimetry Questions:
More Ways to Calculate Enthalpy of Reactions Questions: