100 mL of a 0.5 M solution of nitric acid ( HNO_3) was added to 75 mL of a 0.37…
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100 mL of a 0.5 M solution of nitric acid () was added to 75 mL of a 0.37 M solution of sodium benzoate () the conjugate base of benzoic acid (). Calculate the of the resulting solution.
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