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Introduction to the Heat Curve

Before we take a look at what a heat curve is, we must first understand what can happen when heat is added to a system.

Wize Concept
When heat is added to a system, the system can EITHER:

1) Experience a phase change: q=nΔHphase change or depending on units it could be  q=mΔHphase change\boxed{q=n\Delta H_{phase\ change}}\ \text{or depending on units it could be }\ \boxed{q=m\Delta H_{phase \ change}}

OR
2) Experience a temperature change: q=mcΔT\boxed{q=mc\Delta T}

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More Information on Each of These Important Equations


q=nΔHphase change\boxed{q=n\Delta H_{phase\ change}}

q is heat
n is moles
ΔHphase change is the enthalpy value that describes the heat of transition (energy required to complete a transition)

Example: the heat of vapourization (ΔHvap) is describing the amount of energy that is required to convert a liquid → gas (vapourization).

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q=mcΔT\boxed{q=mc\Delta T}

q is heat
m is mass (g)
c is the specific heat capacity (J/goC or J/goK)
ΔT is the change in temperature ΔT=Tf-Ti (oC or oK)

Wize Tip
For H2O(l), c=4.18J/goC. This means that it takes 4.2 J of heat energy to heat up 1 g of liquid water by 1oC!

Note: Each phase will have a different "c" value!

Example: We will see that water in liquid form and solid ice form have different c values!
  • H2O(l), c=4.18 J/goC
  • H2O(s), c=2.06 J/goC
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Heat curve for H2O

Photo by Cawang / CC BY

  • Label the melting and boiling points of water on the y axis.
  • Label what is happening on the horizontal lines as we move to the right.
  • Label the appropriate equation for each column in the diagram (q=mcΔT or q=nΔH).
  • What c values and ΔH values would you use in each column?
  • What is the slope of horizontal sections?
    0
  • Are the phase changes occuring at the parts of the graph that have a slope of 0 or a positive slope?
    0

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Summary

Photo by Cawang / CC BY


Wize Concept
The horizontal regions on the graph show when a phase change is occurring. We know this because there is no ΔT at these horizontal lines.

We said we can either have a phase change OR a temperature change.
During a phase change, all the heat is being used to overcome the intermolecular forces to make the phase change possible!

Once a phase change has occurred, then the heat increases the temperature (this is where we see the positive slopes)!


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Important Things to Know About the Heat Curve

Photo by Cawang / CC BY

Do you think the ΔHfusion or ΔHvapourization would be a larger number? Why? (You can look at the heat curve to help you decide)
  • ΔHvap because there are more intermolecular forces that need to be broken to go from liquid to gas than there are from solid to liquid.
  • This is because gases have no intermolecular forces (or almost none) so to go from a liquid to a gas, it requires more energy since all the intermolecular forces need to be broken.
  • This will always be the case!
  • The longer the horizontal line in the heat curve, the more/less:
    more
    the value of the ΔH for that phase change!
  • qvap will also be greater than qfusion

Based on the given values of ΔHfusion and ΔHvapourization in the diagram above, what do you think the ΔHcrystallization and ΔHcondensation would be?
Same magnitude but opposite sign so for crystallization it would be -6 kJ and for condensation it would be -40 kJ

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Melting/Boiling Points

The melting point is the temperature where (
s
) ⇌ (
l
) phase

The boiling point is the temperature where (
l
) ⇌ (
g
) phase

Both these points (melting and boiling) occur at a pressure of 1atm. We'll see how this will come in handy for us to know soon!


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Example: Heat Curve

What is the amount of heat required to melt 10 g of ice at -5oC and convert it to liquid at 60oC?
cice=2.06J/goC, ΔHfus=334J/g, cH2O(l)=4.18J/goC

Photo by Cawang / CC BY


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Hint: For a problem like this we need to think of what we are doing (increasing temperature or changing phase) and when
  1. We start with ice at -5oC. The ice will need to be heated until it reaches 0oC
  2. At 0oC we then change ice's phase into liquid by melting it
  3. Once we melt the ice into a liquid, we then heat the liquid from 0oC to 60oC
Now that we have thought of the different steps, let's write out an equation that describes each step:

qT=mciceΔT + nΔHfusion + mcwaterΔT
=(10g)(2.06J/goC)(5oC) + (10g)(334J/g) + (10g)(4.18J/goC)(60oC)
=5951J

If we wanted to answer in kJ, what would be our answer (if our answer only has 2 significant digits):
=5.951 kJ
=6.0 kJ


Watch Out!
Pay attention to the units for these problems, convert units if neccessary.

Practice: Solve for Heat

If we are told that water's heat of fusion (ΔHfus) is 6kJ/mol, then how much heat would be required to melt 5 moles of water?


Practice: Heat Curve

Consider the heat curve below and the following statements:
1 The segment A-B corresponds to the heating of a solid. 2. The segment D-E corresponds to the vaporization of a liquid. 3. The segment E-F corresponds to the heating of a liquid 4. The segment B-C corresponds to a phase change.
Fill in the following table with a + or - depending on if the system will gain or lose energy.
Physical ChangeEnthalpy Change (+=energy is added to the system, -=system loses energy) Enter + or - as answer!
Melting/Fusion
Freezing
Vapourization
Condensation