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Similar Triangles

Similar triangles are triangles that have the same shape but different sizes.

How can we tell if two triangles are similar?

  • Using angles: The corresponding angles (angles in the same relative positions) are all the same Example: A=D\angle A=\angle D, B=E\angle B=\angle E, C=F\angle C=\angle F We say that ABC  DEF\triangle ABC ~\sim~\triangle DEF.

  • Using side lengths: The corresponding sides (sides in the same relative positions) have the same proportions Example: ABRP=BCPQ=CAQR=2\dfrac{AB}{RP}=\dfrac{BC}{PQ}=\dfrac{CA}{QR}=2 We say that ABC  RPQ\triangle ABC~\sim~\triangle RPQ.

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Construct a point along a segment at a given ratio


Our goal in this construction is to draw a point along a given segment, where the the distance to the endpoints is a given ratio.

Using Technology


Begin with segment AB\overline{AB}, and a ratio a:ba : b.
For this demonstration we'll use a=2a = 2, and b=3b = 3.
  1. Draw a point off the line segment AB\overline{AB}. Label this as point CC.
  2. Draw the ray AC\overrightarrow{AC}step.
  3. Use the circle tool circle centered at AA. Label this as point P1P_1.
  4. Use the compass tool to draw a circle of radius AP1\overline{AP_1}, centered at P1P_1. Label the intersection of the circle and the ray as P2P_2 .
  5. Repeat step 4 to mark out equally spaced points until you reach P5P_5.
  6. Draw the segment P5B\overline{P_5 B}
  7. Construct a line parallel to P5B\overline{P_5 B} , and through the point P4P_4. Label the intersection of the line and the segment AB\overline{AB} as Q4Q_4.
  8. Repeat step 7 for all of the points PiP_i
  9. The points Q1Q_1 to Q4Q_4 subdivide AB\overline{AB} into 5 congruent segments.
  10. Relabel Q2Q_2 as point DD.
From this we now have that the ratio of AD\overline{AD} to DB\overline{DB}, is 2 to 3.
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Example: Similar Triangles

Determine if the following triangles are similar.
Using Angles
  • Triangle 1: The 2 given angles in the first triangle are 20°20\degree and 90°90\degree. Since the sum of the interior angles in a triangle is 180°180\degree, we know that the missing angle is 70°70\degree.
  • Triangle 2: The 2 given angles in the second triangle are 20°20\degree and 90°90\degree . Similar to the first triangle, we know that the missing angle is 70°70\degree.
Matching up the same angles, we see that ABC  QPR\triangle ABC~\sim~\triangle QPR.


Using Sides
  • Triangle 1: Using Pythagorean's theorem, we see that BC9.75cmBC\approx 9.75cm
  • Triangle 2: Using Pythagorean's theorem, we see that PR2.44PR\approx2.44
Matching up the sides:
  • longest sides: ACQR=123=4\dfrac{AC}{QR}=\dfrac{12}{3}=4
  • medium sides: BCRP9.752.444\dfrac{BC}{RP}\approx\dfrac{9.75}{2.44}\approx4
  • shortest sides: ABQP=71.75=4\dfrac{AB}{QP}=\dfrac{7}{1.75}=4
Since the corresponding side lengths have the same proportions, we see that ABC  QPR\triangle ABC~\sim~\triangle QPR.

Practice: Similar Triangles

If ABC\triangle ABC is similar to DEF\triangle DEF, solve for the missing variables w,x,y,z,p,qw, x, y, z, p, q.

Practice: Similar Triangle

Identify the similar triangles in the following diagrams, then find the missing lengths.


Practice: Similar Triangles

A flashlight that is placed on the ground is pointed at a brick wall that is 20m away. A basketball player who is 1.9m tall stands 4m in front of the flashlight. Determine the height of the shadow of the basketball player that is cast on the brickwall.