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What to do when the limit is 0/0?

After direction substitution, if you get 00\frac{0}{0}, try the following:
  1. FACTORING: Factor the numerator and denomincator fully, then cancel out any common factors
  2. RATIONALIZING: If it involves ...±a\sqrt{...}\pm a, try multiplying by the conjugate ...∓a...∓a\frac{\sqrt{...}\mp a}{\sqrt{...}\mp a}
  3. ABSOLUTE VALUES: If it involves absolute values, rewrite it without | | signs, then simplify
  4. SUBSTITUTION (a.k.a. change of variable): If you can't factor the numerator and denominator, but they both involve some radical of xx (ex. x1/ax^{1/a} and x1/bx^{1/b}) , let u=xLCD of 1/a &1/b\displaystyle u=x^{\text{LCD of 1/a \&1/b}}

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Examples
  1. Factor: lim⁡x→2 x2−4x−2\displaystyle\lim_{x\to2}\ \frac{x^2-4}{x-2}
  2. Factor: lim⁡h→0 4−(5h+2)2h\displaystyle\lim_{h\to0}\ \frac{4-\left(5h+2\right)^2}{h}
  3. Factor: lim⁡t→1 3t−31−t\displaystyle\lim_{t\to1}\ \frac{\frac{3}{t}-3}{1-t}
  4. Rationalizing: lim⁡x→1 x2+3−2x−1\displaystyle\lim_{x\to1}\ \frac{\sqrt{x^2+3}-2}{x-1}
  5. Rationalizing: lim⁡x→0 xx+4−4−x\displaystyle\lim_{x\to0}\ \frac{x}{\sqrt{x+4}-\sqrt{4-x}}
  6. Absolute Values: lim⁡x→1− ∣x−1∣x2−1\displaystyle\lim_{x\to1^-}\ \frac{|x-1|}{x^2-1}
  7. Absolute Values: lim⁡x→0 ∣3−2x∣−∣2x−3∣x\displaystyle\lim_{x\to0}\ \frac{\left|3-2x\right|-\left|2x-3\right|}{x}
  8. Absolute Values: lim⁡x→2 x−2∣5x−10∣\displaystyle\lim_{x\to2}\ \frac{x-2}{|5x-10|}
  9. Substitution: lim⁡x→64 x3−4x−8\displaystyle \lim_{x\to64}\ \frac{\sqrt[3]{x}-4}{\sqrt{x}-8}
  10. Substitution: lim⁡x→0 (x+27)13−3x\displaystyle \lim_{x\to0}\ \frac{\left(x+27\right)^{\frac{1}{3}}-3}{x}
  11. Substitution: lim⁡x→0 x+16−1x\displaystyle \lim_{x\to0}\ \frac{\sqrt[6]{x+1}-1}{\sqrt{x}}