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Inverse Functions

An inverse function is a function in which the x and y values have switched.
  • Denoted by f1(x) f^{-1}(x)~
  • Pronounced 'f inverse x'
Two functions, f(x) and g(x), are inverses of each other if the following 2 properties are true:
  1. (fg)(x)=x(f\circ{g})(x)=x
  2. (gf)(x)=x(g\circ{f})(x)=x

Note: (fg)(x)=f(g(x))(gf)(x)=g(f(x))(f\circ{g})(x)=f(g(x))\newline{}\newline(g\circ{f})(x)=g(f(x))




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Horizontal Line Test


If any horizontal line intersects the graph of a function f(x)f\left(x\right) at more than one point, then f(x)f\left(x\right) is not one-to-one. If a function is not one-to-one, it cannot have an inverse function.

Example
Find the inverse of the function y=x2y=x^2.
f(x)=y=x2x=y2    Switch x & yy=±x    Solve for yf1(x)=±x\begin{array} {} f(x)=y=x^2\\\\ x=y^2&~~~~\color{green}\footnotesize{\text{Switch x \& y}}\\\\ y=\pm\sqrt{x}&~~~~\color{green}\footnotesize{\text{Solve for y}}\\\\ f^{-1}(x)=\pm\sqrt{x} \end{array}
f1(x)=±xf^{-1}(x)=\pm\sqrt{x}

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Example: Inverse Functions

Given f(x)=2x2+1f(x)=2x^2+1:
  1. Find the inverse f1(x)f^{-1}(x)
  2. Determine the domain and range for f(x)f(x) and compare it to the domain and range for f1(x)f^{-1}(x)

Part 1.

f(x)=2x2+1x=2f1(x)2+1x1=2f1(x)2f1(x)=±x12f(x)=2x^2+1\newline{}\newline x=2{f^{-1}(x)}^2+1\newline{}\newline{} x-1=2{f^{-1}(x)}^2\newline{}\newline f^{-1}(x)=\pm\sqrt{\frac{x-1}{2}}

Part 2.

For f(x)=2x2+1f(x)=2x^2+1:
Domain: (,)(-\infin,\infin)
Range: [1,)[1,\infin)


For f1(x)=±x12f^{-1}(x)=\pm\sqrt{\frac{x-1}{2}}:
Domain: [1,)[1,\infin)
Range: (,)(-\infin,\infin)

Practice: Inverse Functions

True or False:

The inverse of the function y=3x2+1y=-3x^2+1 is f1(x)=±1x3f^{-1}(x)=\pm \sqrt{\frac{1-x}{3}}

Practice: Inverse Functions

Let f(x)=1x+1f(x)=\frac{1}{x}+1. Find f1(x)f^{-1}(x).

Practice: Inverse Functions

If f1(x)=2xx3,f^{-1}(x)=\frac{2x}{x-3}, then determine f(x)f(x).
Extra Practice