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Example: Preparing a Buffer With a Desired pH

How many moles of NaCH3COO should be added to 700mL of a 0.15M of CH3COOH to get a pH of 4.8? Assume no volume change. pKa=4.75

moles of NaCH3COO?
V=700mL (CH3COOH)
c=0.15M (CH3COOH)
pH=4.8
pKa=4.75


Use Henderson Hassalbalch equation:
pH=pKa + log ([conj base]/[conj acid])
4.8=4.75 + log[CH3COO-]/[CH3COOH]
We can solve for moles of CH3COOH and plug that value in so we can solve for the moles of CH3COO-
n=cv
n=0.15M(0.7L)
n=0.105 moles

0.05=log[CH3COO-]/0.105
10^0.05=[CH3COO-]/0.105
CH3COO-= 0.1178 moles ~ 0.12 moles

Extra Practice
Based on the given ionization constants, which of the following pairs of substances should be dissolved together in water to produce a buffer with pH = 9.85?
AcidKaBaseKbAcetic acid (CH3COOH)1.8×105Ammonia (NH3)1.8×105Bicarbonate (HCO3)4.8×1011Acetate (CH3COO)5.6×1010Carbonic acid (H2CO3)4.2×107Aniline (C6H5NH2)3.8×1010Hydrazoic acid (HN3)1.9×105Hydrazine (N2H4)8.5×107Hydrofluoric acid (HF)6.8×104Methylamine (CH3NH2)4.4×104Phenol (C6H5OH)1.3×1010Pyridine (C5H5N)1.5×109\def\arraystretch{2} \begin{array}{c|c|c|c} \hline \rm Acid &\rm K_a & \rm Base & \rm K_b\\ \hline \rm Acetic\ acid \ (CH_3COOH) &1.8 × 10^{−5} & \rm Ammonia \ (NH_3) & 1.8 × 10^{−5} \\ \hline \rm Bicarbonate \ (HCO_3^−) & 4.8 × 10^{−11} & \rm Acetate \ (CH_3COO^−) & 5.6 × 10^{−10} \\\hline \rm Carbonic \ acid \ (H_2CO_3) &4.2 × 10^{−7} &\rm Aniline \ (C_6H_5NH_2) & 3.8 × 10^{−10}\\ \hline \rm Hydrazoic \ acid \ (HN_3) &1.9 × 10^{−5} &\rm Hydrazine \ (N_2H_4) & 8.5 × 10^{−7}\\ \hline \rm Hydrofluoric \ acid \ (HF) & 6.8 × 10^{−4}& \rm Methylamine \ (CH_3NH_2) &4.4 × 10^{−4}\\ \hline \rm Phenol \ (C_6H_5OH) & 1.3 × 10^{−10}&\rm Pyridine \ (C_5H_5N) &1.5 × 10^{−9}\\ \hline \end{array}