Quadratic Surfaces and Level Curves


  • In R3\mathbb{R}^3 space, quadric surfaces are a set of points with general (x,y,z)(x,y,z) coordinates satisfying a polynomial equation.
  • We can sketch these surfaces by using traces, which are curves generated by the intersection of the surface with the planes parallel to the coordinate planes.
  • Traces are also known as level surfaces.
  • To find level surfaces you should takes one variable constant.
  • For example, if we take z=kz=k, then we will have a curve in the plane z=kz=k.
The following will highlight the properties of the main 6 quadratic surfaces: ellipsoid, hyperboloid of one & two sheets, elliptic cone & parabaloid, and hyperbolic paraboloid (the following images are from math.libretexts.org)

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Ellipsoid

x2a2+y2b2+z2c2=1\bf\colorOne{\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2}=1}

  • Traces
  • In the plane z=kz=k, where kRk\in\mathbb{R}: an ellipse
  • In the plane y=my=m, wh
  • ere mRm\in\mathbb{R}: an ellipse
  • In the plane x=nx=n, where nRn\in\mathbb{R}: an ellipse
  • If a=b=ca=b=c, then this surface is a sphere

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Hyperboloid of One Sheet

x2a2+y2b2z2c2=1\bf\colorOne{\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}-\dfrac{z^2}{c^2}=1}

  • Traces
  • In the plane z=kz=k, where kRk\in\mathbb{R}: an ellipse
  • In the plane y=my=m, where mRm\in\mathbb{R}: a hyperbola
  • In the plane x=nx=n, where nRn\in\mathbb{R}: a hyperbola
  • The axis of the surface/direction of opening corresponds to the variable with the negative coefficient

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Hyperboloid of Two Sheets

z2c2x2a2y2b2=1\bf\colorOne{\dfrac{z^2}{c^2}-\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1}

  • Traces
  • In the plane z=kz=k, where kRk\in\mathbb{R}: an ellipse or no trace
  • In the plane y=my=m, where mRm\in\mathbb{R}: a hyperbola
  • In the plane x=nx=n, where nRn\in\mathbb{R}: a hyperbola
  • The axis of the surface/direction of opening corresponds to the variable with the positive coefficient
  • The surface does not intersect the coordinate plane perpendicular to the direction of opening


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Elliptic Cone

x2a2+y2b2z2c2=0\bf\colorOne{\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}-\dfrac{z^2}{c^2}=0}

  • Traces
  • In the plane z=kz=k, where kRk\in\mathbb{R}: an ellipse
  • In the plane y=my=m, where mRm\in\mathbb{R}: a hyperbola
  • In the plane x=nx=n, where nRn\in\mathbb{R}: a hyperbola
  • In the xzxz - plane (y=0y=0): a pair of lines that intersect at the origin
  • In the yzyz - plane (x=0x=0): a pair of lines that intersect at the origin
  • The axis of the surface/direction of opening corresponds to the variable with the negative coefficient.
  • The traces in the coordinate planes parallel to the direction of opening are intersecting lines


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Elliptic Paraboloid

z=x2a2+y2b2\bf{\colorOne{z=\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}}}

  • Traces
  • In the plane z=kz=k, where kRk\in\mathbb{R}: an ellipse
  • In the plane y=my=m, where mRm\in\mathbb{R}: a hyperbola
  • In the plane x=nx=n, where nRn\in\mathbb{R}: a parabola
  • The axis of the surface/direction of opening corresponds to the linear variable



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Hyperbolic Paraboloid

z=x2a2y2b2\bf{\colorOne{z=\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}}}

  • Traces
  • In the plane z=kz=k, where kRk\in\mathbb{R}: an hyerbola
  • In the plane y=my=m, where mRm\in\mathbb{R}: a parabola
  • In the plane x=nx=n, where nRn\in\mathbb{R}: a parabola
  • The axis of the surface/direction of opening corresponds to the linear variable



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Example

Determine and sketch the domain for

f(x,y)=20x2+4xy2+2yf\left(x,y\right)=\sqrt{20-x^2+4x-y^2+2y}

z=20x2+4xy2+2yz=\sqrt{20-x^2+4x-y^2+2y}
 z2=20x2+4xy2+2y\Rightarrow\ z^2=20-x^2+4x-y^2+2y

from complete square method:
x2+ax=(x+a2)2a24x^2+ax=\left(x+\frac{a}{2}\right)^{^2}-\frac{a^2}{4}

 z2=20(x2)2+4(y1)2+1\Rightarrow\ z^2=20-(x-2)^2+4-(y-1)^2+1
 z2+(x2)2+(y1)2=25\Rightarrow\ z^2+(x-2)^2+(y-1)^2=25

Sphere with center C=(2,1,0)C=(2,1,0), with radius R=5R=5



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Example

Find the equation of a sphere with centre C(3,5,2)C\left(3,-5,-2\right) and radius 7. What is the intersection of this sphere with the xyxy-plane?

Generally (xa)2+(yb)2+(zc)2=R2(x-a)^2+(y-b)^2+(z-c)^2=R^2, C(a,b,c)C(a,b,c)
 (x3)2+(y+5)2+(z+2)2=49\Rightarrow\ (x-3)^2+(y+5)^2+(z+2)^2=49
xyxy-plain: z=0z=0
(x3)2+(y+5)2+22=49(x3)2+(y+5)2=45\Rightarrow (x-3)^2+(y+5)^2+2^2=49 \Rightarrow (x-3)^2+(y+5)^2=45

this is a circle at C(3,5)C(3,-5)with radius R=45R=\sqrt{45}.

checklist
Mark Yourself Question
  1. Grab a piece of paper and try this problem yourself.
  2. When you're done, check the "I have answered this question" box below.
  3. View the solution and report whether you got it right or wrong.

Practice

Sketch the following and state the axis of opening:

a) y216 + z24=1\frac{y^2}{16}~+~\frac{z^2}{4}=1


b) z=x29 + y29 3z=\frac{x^2}{9}~+~\frac{y^2}{9}~-3

Practice

Find an equation for all points P that satisfy the distance from P to (3, -2, 1) and P is four times the distance to the plane z = 2.