Rational Functions

Rational Functions
A rational function can be expressed as:
where n is the largest exponent in the numerator and m is the largest exponent in the denomiator.
Properties of Rational Functions
- X-Intercepts can be found by setting f(x)=0 and solving for x
- Vertical asymptotes can be found by setting the denominator to 0 and solving for x
- Horizontal asymptotes:
- If n<m: There is a horizontal asymptote at y=0
- If n=m: There is a horizontal asymptote at y=ca
- If n>m: There is no horizontal asymptote. There may be an oblique/diagonal asymptote.
- If factoring the numerator & denominator of f(x), any terms that cancel out indicates where a missing point/hole in f(x)
- The domain is the set of all real numbers except where there are vertical asymptotes & missing points/holes
- The range is the set of all real numbers except where there are horizontal asymptotes in most cases
Example 1
Let's look at f(x)=x+12x−3.

- x-Intercept: (23,0)
- Vertical Asymptote: x=−1
- Horizontal Asymptote: y=2
- Missing Points/Holes: None
- Intervals of Increasing: (−∞,−1) ∪ (−1,∞)
- Intervals of Decreasing: NA
- Domain: (−∞,−1) ∪ (−1,∞)
- Range: (−∞,2) ∪ (2,∞)

Solving Rational Equations
Rational equations are a type of equation containing at least one rational term, g(x)f(x), where f(x) & g(x) are continuous polynomials.
Rational equations can contain non-permissible values (NPV) that identify the restrictions of the domain. They identify the value of the variable that gives a 0 in the denominator.
Example
Solve x−12=x+25, stating any NPV's.
Step 1.
Identify any non-permissible values.
The NPV's are the vertical asymptotes.
Therefore, x=−2,1 otherwise there is a total of 0 in the denominator.
Step 2.
Find the lowest common denominator and multiply each term by it.
The lowest common denominator is (x−1)(x+2).
(x−12=x+25)×(x−1)(x+2) → 2(x+2)=5(x−1)
Step 3.
Solve for ′x′.
2(x+2)2x+43x∴ x====5(x−1)5x−593
Step 4.
Verify.
x−123−12221====x+253+25551✓

Example: Solving Rational Equations
Solve x+53x+x−21=x2+3x−107, stating any NPV's.
Step 1.
Identify any non-permissible values.
The NPV's are the vertical asymptotes.
(x+5)(x−2)x2+3x−10=(x+5)(x−2)===000→→→∴ x∴ x∴ x===−52−5,2
Therefore, x=−5,2 otherwise there is a total of 0 in the denominator.
Step 2.
Find the lowest common denominator and multiply each term by it.
The lowest common denominator is (x+5)(x−2).
(x+53x+x−21=x2+3x−107)×(x+5)(x−2) → 3x(x−2)+(x+5)=7
Step 3.
Solve for ′x′.
3x(x−2)+(x+5)3x2−6x+x+53x2−5x−2(3x2−6x)+(x−2)(3x+1)(x−2)∴ x======77000−31,2
According to the NPV's, x=2.
Therefore, x=2 is an extraneous solution.
Step 4.
Verify.
x+53x+x−21(−31)+53(−31)+(−31)−21−143−73−149====x2+3x−107(−31)2+3(−31)−107−149−149 ✓
Therefore, x=−31 is the only solution.

Example: Rational Functions
A graph of the function f(x)=x2−3x−4x2−6x+8 is sketched below:

Identify the equations for any vertical & horizontal asymptotes, and missing points/holes.
Factor f(x):
f(x)f(x)f(x)===x2−3x−4x2−6x+8(x−4)(x+1)(x−4)(x−2)x+1x−2
Vertical Asymptotes:
Let x+1=0.
The vertical asymptote is at x=−1.
Horizontal Asymptote:
The degree of the numerator is equivalent to the degree in the denominator.
Therefore, y=1.
Missing Points/Holes
Missing points/holes exist whenever terms in the numerator and denominator cancel.
Since the term (x−4) was eliminated, there is a missing point/hole at x=4.
Identify the vertical asymptotes, the horizontal asymptotes, the x-intercepts, and any missing points of:
f(x)=x2−3x+2x2−11x+18