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Introduction to Titrations

Acid-base titrations are neutralization reactions between a titrant (solution in the buret) and analyte (solution in the flask).



Image illustrating Introduction to Titrations

Photo by Rice University / CC BY



Image illustrating Introduction to Titrations

Titrant

  • Solution in the buret
  • We control the amount we add of the titrant to the flask
  • We know its volume, concentration, and identity Example: 1M 100mL NaOH
  • It is usually a strong acid or base


Analyte

  • Solution in the flask
  • It is the unknown (we don't know its concentration, identity, or if it is weak or strong)
  • We do know it's volume (can easily measure its volume in the flask) and its pH (we can simply use a pH meter to measure this in the flask)
  • The other way to know if there's a pH change in the flask is if we see a visual change in color
  • Indicators help to indicate this pH change by changing the color inside the flask
  • When the color changes, we call this an end-point.





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Labeling a Titration Curve

A plot showing the pH of the solution as a function of the quantity of acid or base added is known as a titration curve.


Image illustrating Labeling a Titration Curve

Photo by Rice University / CC BY


The titrant (substance in the buret that is being added to the analyte in the flask slowly overtime) is: ________

What is the volume for the equivalence point? ________

What is the volume for the half equivalence point? ________





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Titration Curves

1. Strong Acid – Strong Base (HCl(aq) and NaOH(aq))


Image illustrating Titration Curves

Photo by Rice University / CC BY


  • pH is low initially
  • As base is added, the pH increases slowly.
  • The pH rises steeply when the moles of OH- nearly equals the moles of H3O+
  • pH ________ 7 at equivalence point
  • The additional drop of base neutralizes the tiny excess acid and introduces a tiny excess of base
  • Then, pH increases smoothly as more base is added.

2. Weak acid – Strong base Titration (CH3COOH(aq) with NaOH(aq))

Image illustrating Titration Curves

Photo by Rice University / CC BY

  • In a weak acid – strong base titration: pH ________ 7 at the equivalence point
  • Past the equivalence point: pH determined by the [OH-] from the excess strong base. You need the total volume of the solution to determine [OH-]

Calculating pH at different points in the titration

At the start: solution of the weak acid, CH3COOH; use ICE table and Ka to determine pH

CH3COOH(aq)+H2O(ℓ)⇌CH3COO−(aq)+H3O+(aq)CH_3 COOH(aq)+H_2 O(\ell)⇌CH_3 COO^- (aq)+H_3 O^+ (aq)



Between the start and equivalence point: buffer region due to presence of both CH3COOH and CH3COO-; determine moles of acid left unreacted and moles of base produced. Use Henderson – Hasselbach equation to solve for pH.

CH3COOH(aq)+OH−(aq)→CH3COO−(aq)+H2O(ℓ)CH_3 COOH(aq)+OH^- (aq)\to CH_3 COO^- (aq)+H_2 O(\ell)



At half equivalence point: pH = pKa


At equivalence point: all CH3COOH has been converted to CH3COO-; the pH is controlled by the acetate ion, and is thus basic.

CH3COO−(aq)+H2O(ℓ)⇌CH3COOH(aq)+OH−(aq)CH_3 COO^-(aq)+H_2 O(\ell)⇌CH_3 COOH (aq)+OH^- (aq)



Past the equivalence point: pH determined by the [OH-] from the excess strong base. You need the total volume of the solution to determine [OH-]



3. Weak base –Srong acid Titration: (NH3 and HCl)


Draw the titration curve where HCl(aq) is the titrant and being added in gradually.


Image illustrating Titration Curves


  • In a weak base – strong acid titration: pH ________ 7 at the equivalence point
  • Past the equivalence point: pH determined by the [H3O+] from the excess strong acid

Calculating pH at different points in the titration

At the start: solution of the weak base, NH3; use ICE table and Kb to determine pH

NH3(aq)+H2O(ℓ)⇌NH4+(aq)+OH−(aq)NH_3(aq)+H_2O(\ell)⇌NH_4^+(aq)+OH^-(aq)



Between the start and equivalence point: buffer region due to presence of both NH3 and NH4+ determine [NH3] left unreacted and [NH4+] produced; use Henderson-Hasselbach equation to determine pH

NH3(aq)+H3O+(aq)→NH4+(aq)+H2O(ℓ)NH_3 (aq)+H_3 O^+ (aq)\to NH_4^+ (aq)+H_2 O(\ell)



At half equivalence point: pH = pKa of NH4+

At equivalence point: all NH3 has been converted to NH4+; use Ka of NH4+ to determine [H3O+]

NH4+(aq)+H2O(ℓ)⇌NH3(aq)+H3O+(aq)NH_4^+(aq)+H_2O(\ell)⇌NH_3(aq)+H_3O^+(aq)




Past the equivalence point: pH determined by the [H3O+] from the excess strong acid




Practice: Equivalence Point

For which type of titration will the pH be basic at the equivalence point?

Choose an answer

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