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PV Diagrams & Thermodynamic Processes

  • The system is taken from some initial state to some final state.
  • Every line in a PV-diagram is a thermodynamic process.
  • There are four well known thermodynamic processes


Image illustrating PV Diagrams & Thermodynamic Processes
  • The adiabatic line is always steeper than the isothermal line because:
  • In an isothermal process: P=nRTV∝1VP=\frac{nRT}{V}\propto\frac{1}{V}
  • In an adiabatic process: P=ConstantVγ∝1Vγ, γ>1P=\frac{Constant}{V^\gamma} \propto\frac{1}{V^\gamma},\ \gamma>1


Work done on an ideal gas

Work done on the gas during a thermodynamic process is the area under the PV curve, from initial state (i) to final state (f).

Won the gas=∫PdVW_{on \ the\ gas} =\int PdV


EXPANSION of the gas COMPRESSION of the gas
Image illustrating PV Diagrams & Thermodynamic Processes


Image illustrating PV Diagrams & Thermodynamic Processes



A Carnot engine is operated between ��H and ��C according to the PV – Diagram given below where the processes 𝑎 → 𝑏 and 𝑐 → 𝑑 are isothermal and the processes 𝑏 → 𝑐 and 𝑑 → 𝑎 are adiabatic.



Image illustrating Example: PV Diagram


a) Find the efficiency of this engine as a function of ��C and ��H

b) Show Carnot Cycle in TS –diagram


Solution:


Image illustrating Example: PV Diagram

a) Qbc=Qda=0 adiabaticQ_{bc}=Q_{da}=0\ adiabatic


Qab:ΔT=0→Wab=Qab>0Q_{ab}:\Delta T=0\to W_{ab}=Q_{ab}>0


Qab=nRTHln⁡(VbVa)Q_{ab}=nRT_H\ln\left(\frac{V_b}{V_a}\right)


Qcd=Wcd<0→Qcd=nRTc ln⁡(VdVc)Q_{cd}=W_{cd}<0\to Q_{cd}=nRT_c\ \ln\left(\frac{V_d}{V_c}\right)


e=1+QcQH=1+TcTH ln⁡(VdVc)ln⁡(VbVa)e=1+\frac{Q_c}{Q_H}=1+\frac{T_c}{T_H}\ \frac{\ln\left(\frac{V_d}{V_c}\right)}{\ln\left(\frac{V_b}{V_a}\right)}


TVγ−1=constTV^{\gamma-1}=const for adiabatic processes


for b→c: THVbγ−1=TcVcγ−1→THTC=(VcVb)γ−1b\to c:\ T_HV_b^{\gamma-1}=T_cV_c^{\gamma-1}\to\frac{T_H}{T_C}=\left(\frac{V_c}{V_b}\right)^{\gamma-1}


for d→a: TCVdγ−1=THVaγ−1→THTC=(VdVa)γ−1d\to a:\ T_CV_d^{\gamma-1}=T_HV_a^{\gamma-1}\to\frac{T_H}{T_C}=\left(\frac{V_d}{V_a}\right)^{\gamma-1}


→VcVb=VdVa or VdVc=VaVb\to\frac{V_c}{V_b}=\frac{V_d}{V_a}\ or\ \frac{V_d}{V_c}=\frac{V_a}{V_b} plug into efficiency equation


→e=1−TcTH\to e=1-\frac{T_c}{T_H}

b)

Image illustrating Example: PV Diagram


0.08 mole of nitrogen undergoes the following process. What is the work done on the gas?

Illustration for practice question: First Law of Thermodynamics



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Two moles of a monatomic gas undergo some thermodynamic processes as shown in the following plot. (The expansion from a to b is adiabatic). What is the net work done by the gas during a full cycle? (As a function of ��𝑜 and 𝑉𝑜)

Illustration for practice question: Thermodynamic Processes



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Extra Practice