Given the following reaction, if we start with 16moles of CH2=CHCH3(g), 16 moles of NH3(g) and 320moles of O2(g) in a 1L container, what will the equilibrium concentration be for H2O(g)?
CH2=CHCH3(g) + NH3(g) + 32O2(g) ⇌ CH2=CHC≡N(g) + 3H2O(g) K=1.2×1094
For this problem, since the K value is very large, the reaction will go to completion. We will have 1 ICE table for the reaction going to completion and a second ICE table for the reverse reaction where we will find the equilibrium concentrations!
Forward Reaction ICE Table:
CH2=CHCH3(g) + NH3(g) + 32O2(g) ⇌ CH2=CHC≡N(g) + 3H2O(g) K=1.2×1094
I 16M 16M 320M 0 0
Reverse Reaction ICE Table:
CH2=CHC≡N(g) + 3H2O(g) ⇌ CH2=CHCH3(g) + NH3(g) + 32O2(g)
What is our K expression now for this reverse reaction?
What is Kreverse?
We can use our K expression to solve for x and then we can use x to solve for the equilibrium concentrations!