Equilibrium Constant

If 1.00 mole of HCl (g) is placed in an 8.00 L container, what will be the concentration of H2 in that container at equilibrium?

2HCl(g)H2(g)+Cl2(g)KC=1.3×1092HCl(g)⇌H_2 (g)+Cl_2 (g) \qquad K_C=1.3×10^{-9}
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