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Consider the following reaction: PCl3 + Cl2 = PCl5 If the yield of the reaction…
Related Topics
Wize University Chemistry Textbook > Stoichiometry
Percent Yield
4 Activities
Consider the following reaction:
PCl
3
+ Cl
2
= PCl
5
If the yield of the reaction is 76.5 %, what is the amount of PCl
5
obtained from 27.0 g of PCl
3
?
Answer
I don't know
Check Submission
More Percent Yield Questions:
Percent Yield
If the yield for the following reaction is 45%, how many moles of KClO
3
are needed to produce 1 mol of O
2
?
2KClO
3
(s) → 2KCl(s) + 3O
2
(g)
Stoichiometry
Consider the following reaction:
2 Ca
3
(PO
4
)
2
(s) + 10 C (s) + 6 SiO
2
(s) → 6 CaSiO
3
(s) + 10 CO (g) + P
4
(l)
An initial reaction mixture contains 15.0 g Ca
3
(PO
4
)
2
, 10.0 g SiO
2
, and 4.00 g C. After the reaction, 2.17 g P
4
is obtained. What is the percent yield for this experiment?
Chemical Reactions: Actual Yield
Consider the following reaction:
P
C
ℓ
3
+
C
ℓ
2
→
P
C
ℓ
5
PC\ell_3 + C\ell_2 \to PC\ell_5
P
C
ℓ
3
+
C
ℓ
2
→
P
C
ℓ
5
If the yield of the reaction is 76.5 %, what is the mass of PCl
5
, in grams, obtained from the reaction of 27.0 g of PCl
3
with excess Cl
2
? Give your answer to one decimal place; do not include units in your answer.
Stoichiometry: Percent yield
In the balanced reaction below, a student reacts 1.25g of copper with 5.0mL of 12.0mol/L HCl.
C
u
(
s
)
+
2
H
C
ℓ
(
a
q
)
→
C
u
C
ℓ
2
(
a
q
)
+
H
2
(
g
)
Cu(s)+ 2HC \ell(aq)\to CuC\ell_2(aq) +H_2(g)
C
u
(
s
)
+
2
H
C
ℓ
(
a
q
)
→
C
u
C
ℓ
2
(
a
q
)
+
H
2
(
g
)
Stoichiometry: Limiting Reagents
Vanillin acetate is a synthetic flavoring agent used to mimic the natural flavor of vanilla in candies, beverages, ice creams, and baked goods. You only need 10-30 ppm concentrations of vanillin acetate to flavor most foods! The preparation of this compound is described by the balanced reaction scheme below. Use the data provided to answer the following questions.
Chemical reactions: Limiting Reagent & Percent Yield
Iron oxidizes when exposed to oxygen to form iron oxide according to the following equation:
Fe (s) + O
2
(g) → Fe
2
O
3
(s)
352g of pure iron is exposed to 12.0 mols of O
2
, and after a period of time, 46.7 g of iron oxide (rust) is collected.
Stoichiometry 2
An unknown hydrocarbon contains 40.0% C and 6.66% H by weight.
a. What is the empirical formula of the compound?
b. What is the molecular formula if molecular weight of the compound is 180 gmol
-1
?
Stoichiometry
Consider the following reaction:
2 Ca
3
(PO
4
)
2
(s) + 10 C (s) + 6 SiO
2
(s) → 6 CaSiO
3
(s) + 10 CO (g) + P
4
(l)
An initial reaction mixture contains 15.0 g Ca
3
(PO
4
)
2
, 10.0 g SiO
2
, and 4.00 g C. After the reaction, 2.17 g P
4
is obtained. What is the percent yield for this experiment?
Consider the two following reactions:
CS
2
+ 3Cl
2
→ CCl
4
(l)+ S
2
Cl
2
(l) 60% yield
3 CCl
4
(l) + 2 SbF
3
(s) → 3 CCl
2
F
2
(g) + 2SbCl
3
(s) 80% yield
Precipitation
Zinc reacts with silver nitrate according to the following equation:
Zn (s) + 2AgNO
3
(aq) → Zn(NO
3
)
2
(aq) + 2Ag (s)
The concentration of AgNO
3
solution is 1.330 molsL
-1
. 100 g Zn was added to 1.000 L of this solution and 90.0 g Ag is collected. What is the percent yield of this reaction?
Precipitation
CaSO
4
can be converted to CaO at high temperature by the following two step procedure:
CaSO
4
(s) + 4C → CaS (l) + 4CO (g)
CaS (l) + 3CaSO
4
(s) → 4CaO (s) + 4SO
2
Percent Yield
Sodium carbonate is an inexpensive compound that has a variety of applications. It is used in glass and paper manufacturing as well as in common foods like ramen noodles. The production of sodium carbonate occurs in a two step reaction as shown below:
1. H
2
O + NaCl + NH
3
+ CO
2
→ NH
4
Cl + NaHCO
3
2. 2NaHCO
3
→ Na
2
CO
3
+ CO
2
+ H
2
O
Percent Yield
If the yield for the following reaction is 45%, how many moles of KClO
3
are needed to produce 1 mol of O
2
?
2KClO
3
(s) → 2KCl(s) + 3O
2
(g)
CHEM 1011 (Dalhousie) - Stoichiometry
2.
In the unbalanced reaction below, a student reacts 1.25 g of copper with 5.0 mL of 12.0 M HCl.
C
u
(
s
)
+
H
C
l
(
a
q
)
→
C
u
C
l
2
(
a
q
)
+
H
2
(
g
)
Cu\ \left(s\right)\ \ \ \ +\ \ \ \ HCl\ \left(aq\right)\ \ \ \ \rightarrow\ \ \ \ CuCl_2\ \left(aq\right)\ \ \ \ +\ \ \ \ H_2\ \left(g\right)
C
u
(
s
)
+
H
C
l
(
a
q
)
→
C
u
C
l
2
(
a
q
)
+
H
2
(
g
)
a)
Calculate the theoretical yield of hydrogen gas produced in grams.
Stoichiometry: Limiting reagents
3.
Consider the chemical reaction described below:
C
a
3
(
P
O
4
)
2
(
s
)
+
C
(
s
)
+
S
i
O
2
(
s
)
→
C
a
S
i
O
3
(
s
)
+
C
O
(
g
)
+
P
(
l
)
Ca_3\left(PO_4\right)_2\ \left(s\right)\ \ \ \ +\ \ \ \ C\ \left(s\right)\ \ \ \ +\ \ \ \ SiO_2\ \left(s\right)\ \ \ \ \rightarrow\ \ \ \ CaSiO_3\ \left(s\right)\ \ \ \ +\ \ \ \ CO\ \left(g\right)\ \ \ \ +\ \ \ \ P\ \left(l\right)
C
a
3
(
P
O
4
)
2
(
s
)
+
C
(
s
)
+
S
i
O
2
(
s
)
→
C
a
S
i
O
3
(
s
)
+
C
O
(
g
)
+
P
(
l
)
a)
What is the limiting reagent for this reaction if an initial reaction mixture contains 1325 kg of calcium phosphate, 300 kg of carbon and 890 kg of silicon dioxide.
Chemical Reactions: Limiting Reagent
Based on the unbalanced chemical reaction below:
N
a
N
O
2
(
s
)
+
O
2
(
g
)
→
N
a
N
O
3
(
s
)
NaNO_2\ \left(s\right)\ \ \ \ +\ \ \ \ O_2\ \left(g\right)\ \ \ \ \rightarrow\ \ \ \ NaNO_3\ \left(s\right)
N
a
N
O
2
(
s
)
+
O
2
(
g
)
→
N
a
N
O
3
(
s
)
a)
Calculate the mass of sodium nitrate if 10.25 g of sodium nitrite is reacted with 7.55 g of oxygen gas.
Chemical Reactions: Limiting Reagent & Percent Yield Practice
Iron oxidizes when exposed to oxygen to form iron oxide according to the following equation:
Fe + O2 →Fe2O3
352g of pure iron is exposed to 12.0 mols of O2, and after a period of time 46.7 g of iron oxide (rust) is collected.
Chemical Reactions: Percent Yield
If the yield for the following reaction is 45%, how many moles of KClO
3
are needed to produce 1 mol of O
2
?
2KClO
3
(s) -> 2KCl(s) + 3O
2
(g)
Stoichiometry: Mass Percentage
How many grams of PCl
3
are needed to produce 10g of POCl
3
using an excess of hydrogen peroxide assuming a typical reaction yield of 78%?
P
C
l
3
+
H
2
O
2
→
P
O
C
l
3
+
H
2
O
PCl_3+H_2O_2\rightarrow POCl_3+H_2O
P
C
l
3
+
H
2
O
2
→
P
O
C
l
3
+
H
2
O
Stoichiometry: Percent yield
Consider the following unbalanced reaction:
C
4
H
8
O
2
+
O
2
→
C
O
2
+
H
2
O
\rm C_4H_8O_2 +O_2 \to CO_2 + H_2O
C
4
H
8
O
2
+
O
2
→
C
O
2
+
H
2
O
If 36.00 g of
C
4
H
8
O
2
\rm C_4H_8O_2
C
4
H
8
O
2
is burned, what mass of water would be collected if the reaction yield was 76%?
Stoichiometry: Percent Yield
A compound with the formula
C
7
H
8
O
3
\text{C}_7\text{H}_8\text{O}_3
C
7
H
8
O
3
is burned to completion in excess
O
2
\text{O}_2
O
2
. If 18.0g of the organic compound was consumed in the reaction, how many grams of
H
2
O
\text{H}_2\text{O}
H
2
O
will be collected if the yield was 85%?
The potassium salt of benzoic acid, potassium benzoate (KC
7
H
5
O
2
, MM=160 g/mol) can be made by the action of potassium permanganate on toluene (C
7
H
8
, MM=92 g/mol). If the yield of potassium benzoate cannot realistically be expected to be more than 71%, what is the minimum number of grams of toluene needed to produce 11.5 g of potassium benzoate?
C
7
H
8
+
2
K
M
n
O
4
→
K
C
7
H
5
O
2
+
2
M
n
O
2
+
K
O
H
+
H
2
O
C_7 H_8+2KMnO_4→KC_7 H_5 O_2+2MnO_2+KOH+H_2 O
C
7
H
8
+
2
K
M
n
O
4
→
K
C
7
H
5
O
2
+
2
M
n
O
2
+
K
O
H
+
H
2
O
Stoichiometry: Percent Yield
How many grams of PCl
3
are needed to produce 10g of OPCl
3
using an excess of hydrogen peroxide assuming a typical reaction yield of 78%?
PCl
3
+
H
2
O
2
→
OPCl
3
+
H
2
O
Chemical Reactions: Limiting Reagent & Percent Yield Practice
Iron oxidizes when exposed to oxygen to form iron oxide according to the following equation:
Fe + O
2
→Fe
2
O
3
352g of pure iron is exposed to 12.0 mols of O
2
, and after a period of time 46.7 g of iron oxide (rust) is collected.
Percent Yield
If the yield for the following reaction is 45%, how many moles of KClO
3
are needed to produce 1 mol of O
2
?
2KClO
3
(s) -> 2KCl(s) + 3O
2
(g)
Aspirin is produced by the reaction of salicylic acid,
C
7
H
6
O
3
\rm C_7H_6O_3
C
7
H
6
O
3
, and acetic anhydride,
C
4
H
6
O
3
\rm C_4H_6O_3
C
4
H
6
O
3
C
7
H
6
O
3
(
s
)
+
C
4
H
6
O
3
(
l
)
→
C
9
H
8
O
4
(
s
)
+
C
2
H
4
O
2
(
l
)
\rm C_7H_6O_3(s)+C_4H_6O_3(l)\rightarrow C_9H_8O_4(s)+C_2H_4O_2(l)
C
7
H
6
O
3
(
s
)
+
C
4
H
6
O
3
(
l
)
→
C
9
H
8
O
4
(
s
)
+
C
2
H
4
O
2
(
l
)
If 2.04 g of
C
9
H
8
O
4
\rm C_9H_8O_4
C
9
H
8
O
4
is produced from the reaction of 3.03 g
C
7
H
6
O
3
\rm C_7H_6O_3
C
7
H
6
O
3
and 4.01 g
C
4
H
6
O
3
\rm C_4H_6O_3
C
4
H
6
O
3
, what is the percent yield?