Let V=R^2 but with the defined the operations: u + v = (u_1+v_2,u_2+v_1) In t…

Let V=R2V=\mathbb{R}^2 but with the defined the operations:

u+v=(u1+v2,u2+v1)\vec u + \vec v = (u_1+v_2,u_2+v_1)

In this space the zero vector is 0=(0,0)\vec 0 = (0,0)\qquad (can you prove that?)

If this set satisfies the vector space axioms, what is the vector (u1,u2)-(u_1,u_2) in this space?
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