Let Z={ x = (x);|;x>3} with the following operations: u+ v=uv-3(u+v)+12 k⋅ v …

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Let Z={x=(x)    x>3}Z=\{\vec x = (x)\;|\;x>3\} with the following operations:
  • u+v=uv3(u+v)+12\vec u+\vec v=uv-3(u+v)+12
  • kv=(v3)a+3k\cdot \vec v = (v-3)^a+3
Find the zero vector in this vector space
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